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user100 [1]
3 years ago
6

Imagine you are riding on a yacht in the ocean and traveling at 20 mph. You then hit a golf ball at 100 mph from the deck of the

yacht. You see the ball move away from you at 100mph, while a person standing on a near by beach would observe your golf ball traveling at 120 mph (20 mph + 100 mph). Now imagine you are aboard the Hermes spacecraft traveling at 0.1c (1/10 the speed of light) past Mars and shine a laser from the front of the ship. You would see the light traveling at c (the speed of light) away from your ship. According to Einstein’s special relativity, how fast will a person on Mars observe the light to be traveling?
Physics
2 answers:
Novosadov [1.4K]3 years ago
8 0
A naive guess would be 1.1c, according to classical mechanics. But Special relativity posited a new special law of adding velocities; so when one is travelling at 5m/s on a platform moving 5m/s, the result is very very close to 10m/s, but it is not exact. This deviation is more visible in higher speeds. There is a specific formula that gives us the speed of an object when it moves in a frame of reference, but in this case the answer is simple. The speed of light is an absolute barrier to the speed of any object and it is preserved in all frames of reference. Thus, a person will also measure a velocity of c for the light.
Whitepunk [10]3 years ago
6 0

Before solving this question, first we have to understand the special theory of relative.

As per classical mechanics, the velocity of light will be different in different frame of reference. The light moves in the ether medium which exists every where in the entire universe.

Let us consider a body which moves with a velocity v. Let light is coming along the direction of the body. As per classical mechanics,the velocity of light with respect to the body will be [ c-v].

Let us consider that light is coming from opposite direction. Hence, the velocity of light with respect to the observer will be c+v.

From above we see that velocity of light is different in both the cases which is wrong.

As per Einstein's special theory of relativity, the velocity of light will be same in every frame of reference i.e c=300000 km/s.

As per the question ,the space craft is moving with a velocity 0.1 c.

We are asked to calculate the velocity of the light with respect to an observer present in Mars.

Considering Einstein's theory of relativity, the velocity of light will be c [300000 km/s] with respect to the person in Mars.

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Explain in your own words the interaction between the electric and magnetic fields that make up a light wave.
iVinArrow [24]

Answer:

They oscillates perpendicularly to one another, the oscillation of one field generates the other field.

Explanation:

In a light wave, an oscillating electric field of a light wave produces a magnetic field, and the magnetic field also oscillates to produce an electric field. The magnetic field and the electric field of a light wave both oscillates perpendicularly to one another. The resultant energy and direction of the wave generated as a result of these oscillating fields is propagated perpendicularly to both fields.

8 0
3 years ago
How high can a body vertically thrown with a speed of 40m/s raise after 3 sec (neglecting air
Tcecarenko [31]

y = 75.9 m

Explanation:

y = -(1/2)gt^2 + v0yt + y0

If we put the origin of our coordinate system at the point where a body is launched, then y0 = 0.

y = -(1/2)(9.8 m/s^2)(3 s)^2 + (40 m/s)(3 s)

= -44.1 m + 120 m

= 75.9

5 0
3 years ago
Question 9
egoroff_w [7]

Answer:

C

Explanation:

F=ma

given solution

v=12m/s a=v/t

s=6 sec =12m/s÷6sec

=2m/s^2 then we get acceleration now we will find the mass. first derive the the formula of mass by crisis cross then you will get this formula which is m=F/a

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6 0
3 years ago
Unpolarized light with an intensity of 22.4 ????ux passes through a polarizer whose transmission axis is vertically oriented. (a
irina1246 [14]

Answer:

a)      I₁ = 11.2 Lux , vertical direction , b)      I₂ = 1.44 Lux

Explanation:

a) A polarized is a system that absorbs light that is not polarized in the direction of its axis, therefore half of the non-polarized light must be absorbed

consequently the above the processed light has half of the incident intensity and the directional of the polarized

          I₁ = I₀ / 2

          I₁ = 22.4 / 2

          I₁ = 11.2 Lux

is polarized in the vertical direction

b) The polarized light falls on a second polarizer, therefore it must comply with the law of Malus

         I₂ = I₁ cos² θ

         I₂ = 11.2 cos² 69

         I₂ = 1.44 Lux

8 0
3 years ago
Which of the following statements cannot be supported by Kepler's laws of planetary motion? a. The distance of a planet around t
hodyreva [135]

i guess option (a)

is the right one

if it's correct

select me as brainliest

5 0
3 years ago
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