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Dmitry_Shevchenko [17]
3 years ago
13

An object is dropped from a height of 50 meters. Ignoring air resistance, how long doe take to hit the ground?

Physics
1 answer:
Arte-miy333 [17]3 years ago
3 0

here given that object is dropped from height h = 50 m

So here we can say

initial speed is ZERO

acceleration is due to gravity

now in order to find time to reach the ground we can use kinematics

y = v_i*t + \frac{1}{2}at^2

now plug in all values in it

50 = 0 + \frac{1}{2} \times 9.8(t^2)

t = 3.2 s

so it will take 3.2 s to reach the ground

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One car has two and a half times the mass of a second car, but only half as much kinetic energy. When both cars increase their s
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Answer:

v_1 = 7.96 m/s

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3 0
3 years ago
Calculate the angle for the third-order maximum of 580-nm wavelength yellow light falling on double slits separated by 0.100 mm.
alekssr [168]

<u>Answer:</u> The angle of diffraction is 0.498°

<u>Explanation:</u>

To calculate the angle of diffraction, we use the equation given by Bragg, which is:

n\lambda =2d\sin \theta

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n = order of diffraction = 3

\lambda = wavelength of the light = 580nm=5.80\times 10^{-7}m    (Conversion factor:  1m=10^{9}nm )

d = spacing between the crystal planes = 0.100 mm = 1.0\times 10^{-4}       (Conversion factor:  1 m = 1000 mm)

\theta = angle of diffraction = ?

Putting values in above equation:

3\times 5.80\times 10^{-7}=2\times 1.00\times 10^{-4}\sin \theta\\\\\sin \theta = 0.0087\\\\\theta=\sin ^{-1} (0.0087)=0.498

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Answer:

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solution

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