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Dmitry_Shevchenko [17]
3 years ago
13

An object is dropped from a height of 50 meters. Ignoring air resistance, how long doe take to hit the ground?

Physics
1 answer:
Arte-miy333 [17]3 years ago
3 0

here given that object is dropped from height h = 50 m

So here we can say

initial speed is ZERO

acceleration is due to gravity

now in order to find time to reach the ground we can use kinematics

y = v_i*t + \frac{1}{2}at^2

now plug in all values in it

50 = 0 + \frac{1}{2} \times 9.8(t^2)

t = 3.2 s

so it will take 3.2 s to reach the ground

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Approximately 5.9\; {\rm m\cdot s^{-1}} (assuming that the partner is holding the other end of the coil stationary.)

Explanation:

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Thus, if the wavelength of the wave in this question is \lambda, the length of this spring would be:

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The frequency f of this wave is the number of cycles in unit time:

\begin{aligned} f &= \frac{10}{16.3\; {\rm s}} \approx 0.613\; {\rm s^{-1}}\end{aligned}.

Hence, the speed v of this wave would be:

\begin{aligned} v &= \lambda\, f \\ &=9.6\; {\rm m} \times 0.613\; {\rm s^{-1}} \\ &\approx 5.9\; {\rm m \cdot s^{-1}}\end{aligned}.

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