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Westkost [7]
3 years ago
12

Find the length of a pendulum that oscillates with a frequency of 0.15 hz. the acceleration due to gravity is 9.81 m/s 2 . answe

r in units of m.
Physics
1 answer:
SpyIntel [72]3 years ago
7 0
<span>Frequency of the pendulum F = 0.15Hz Acceleration due to gravity g = 9.81 m/s^2 Period of the pendulum is calculated by T = 2 x 3.14 x squareroot of (L / g), L being the length of the pendulam. We have an equation between T and F => T = 1 / F T = 1 / 0.15 => T = 20 / 3 Now substituting the values => 20 / 3 = 2 x 3.14 x squareroot of (L / 9.81) => 3.33 = 3.14 x squareroot of (L / 9.81) => squareroot of (L / 9.81) = 3.33 / 3.14 => L / 9.81 = 1.06^2 => L = 1.13 x 9.81 Length of the pendulum = 11 m</span>
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Serhud [2]
For the answer to the question above, first find out the gradient. 

<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>

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<span>(x2,y2) = (6,62) </span>

<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>

<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>

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</span>I hope this helps.
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Explanation:

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Rufina [12.5K]

<u>Answer:</u>

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ivann1987 [24]

Answer:

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