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Marat540 [252]
3 years ago
10

A heat pump receives heat from a lake that has an average winter time temperature of 6o C and supplies heat into a house having

an average temperature of 25o C. (a) If the house loses heat to the atmosphere at the rate of 60,000 kJ/h, determine the minimum power supplied to the heat pump (in kW) that can maintain the interior temperature of the house at 25o C. (b) Suppose the heat pump absorbs energy from the ground (10o C) instead of the lake, Calculate the minimum power (in kW) required for the heat pump.
Physics
1 answer:
Natalija [7]3 years ago
4 0

Answer:

Explanation:

60000 kJ / h = 60000 x 1000 / (60 x 60 )

= 16667 J /s

a)

\frac{Q_H}{W} =\frac{T_H}{T_H-T_C}

where Q_H and W are heat supplied and heat given from  outside source .

Here Q_H = 16667 J/s

\frac{T_H}{T_H-T_C}=\frac{298}{298-279}

= 15.684

Q_H = 16667 J/s

16667 / W = 15.684

W= minimum power supplied  = 1062.7 W.

b )

If  T_C=283K

\frac{T_H}{T_H-T_C}=\frac{298}{298-283}

=19.87

\frac{Q_H}{W} = 19.87

W=\frac{Q_H}{19.87}

W=\frac{16667}{19.87}

= 838.8 W .

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