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Luda [366]
3 years ago
13

What would happen to the two balls if one of them were kept positively charged and the charge on the other ball were slowly incr

eased, making it more and more positive?
Physics
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

The force of repulsion between the two balls will increase

Explanation:

The electrostatic force between two charged objects is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the charges of the two objects

r is the distance between the centres of the two objects

We see that the magnitude of the force is directly proportional to the charges on the two objects. in this problem, we have two positively charged balls (so, there is a force of repulsion between them, since like charges repel each other and unlike charges attract each other), and the positive charge in one of them is slowly increased: this means that either q_1 or q_2 in the formula is increasing, and so the magnitude of the force is increasing.

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Answer:

Explanation:

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As we know that when we apply heat to a material it expands. The amount of expansion depends on the nature of the material. The amount of expansion depends on the coefficient of thermal expansion of the material.

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Explanation:

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By what factor will the Electrostatic Force between two charged objects change when the amount of charge on both objects doubles
Mademuasel [1]

Answer:

F' = (4/9)F

Explanation:

The electrostatic force between two charged objects is given by Coulomb's Law:

F = kq₁q₂/r²   -------------------- equation (1)

where,

F = Electrostatic Force

k = Coulomb's Constant

q₁ = magnitude of first charge

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r = distance between charges

Now, when the charges and distance altered as follows:

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Then,

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using equation (1):

<u>F' = (4/9)F</u>

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