Answer:
24/49
Step-by-step explanation:
If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.
d^2=x^2+x^2
d^2=2x^2
d=√(2x^2)
Since d=2r, r=d/2 so
r=(1/2)√(2x^2)
r=√((2x^2)/4)
r=√(x^2/2), since x=8
r=√(64/2)
r=√32
r=√(16*2)
r=4√2 in (exact)
r≈5.66 in (to nearest hundredth of an inch)
To solve the problem shown bove you must apply the proccedure shown below:
1. You have that:
2a-1<<span>7−1.2a
2a+1.2a<7+1
3.2a<8
a<8/3.2
a<2.5
2. Therefore, f</span><span>or what values of a is the value of the binomial 2a−1 smaller than the value of the binomial 7−1.2a?
</span><span>
As you can see above, the answer for this question is:
All the values of a between -</span>∞ and 2.5<span>
</span>
27pi in.^2
just got the answer on edge,
edge is the stupidest waste of time I've ever used, gotta get them credits to graduate though.
