Question

Calculate the amount of energy produced in a nuclear reaction in which the mass defect is 0.187456 amu.

Answer 1

For nuclear reactions, we determine the energy dissipated from the process from the Theory of relativity wherein energy is equal to the mass defect times the speed of light. We calculate as follows:

E = mc^2 = 0.187456 (3x10^8)^2 = 1.687x10^16 J

Hope this answers the question.

Answer 2

Answer:

$E = 174.6 MeV$

Explanation:

As we know that energy corresponding to the 1 amu mass is given as

$E = mc^2$

if m = 1 amu

we have

$E = 931.5 MeV$

so we will have

mass = 0.187456 amu

$E = (0.187456)(931.5)$

$E = 174.6 MeV$