Ask question

Ask question

All categories

kakasveta [241]

4 years ago

13

Electrical strain gauges were applied to a notched specimen to determine the stresses in the notch. The results were εx=0.0019 a

nd εy=0.00072. Find σx and σy if the material is made of carbon steel where E=200GPa, Sy=360 MPa.

1 answer:

pickupchik [31]4 years ago

6 0

Answer:

$\sigma_x=451.8MPa$

$\sigma_y=265.99MPa$

Explanation:

$\varepsilon _x=0.0019$

$\varepsilon _y=0.00072$

Poission's ratio for steel =0.28

We know that

$\varepsilon _x=\dfrac{\sigma _x}{E}-\mu\dfrac{\sigma _x}{E}$

$\varepsilon _y=\dfrac{\sigma _y}{E}-\mu\dfrac{\sigma _x}{E}$

Now by putting the values

$0.0019=\dfrac{\sigma _x}{200\times 1000}-0.28\dfrac{\sigma _y}{200\times 1000}$

$0.00072=\dfrac{\sigma _y}{200\times 1000}-0.28\dfrac{\sigma _x}{200\times 1000}$

So $\sigma_x=451.8MPa$

$\sigma_y=265.99MPa$

You might be interested in

Mention verious medium level and higher level human resources related to engineering

aliya0001 [1]

Answer:

Engineering aims to allow technical parts, structures and/or systems, such as those of a machine, to fulfill their function. To this end, occurring and/or desired processes (the operation thereof) are investigated and elaborated. Appropriate parts are designed individually or in a team, occurring stresses are calculated and the parts to be produced are modeled and/or specified on technical drawings. In some fields, maintenance is a standard part of the work to be performed. For a large part of engineering, standards and agreements have been drawn up with a view to the desired safety and practical applicability.

8 0

3 years ago

Using the following data, determine the percentage retained, cumulative percentage retained, and percent passing for each sieve.

vekshin1

Solution :

<u>Sieve Size</u> (in) <u>Weight retain</u><u>(g)</u>

3 1.62

2 2.17

$1\frac{1}{2}$ 3.62

$\frac{3}{4}$ 2.27

$\frac{3}{8}$ 1.38

PAN 0.21

Given :

Sieve weight % wt. retain % cumulative % finer

size retained wt. retain

No. 4 59.5 10.225% 10.225% 89.775%

No. 8 86.5 14.865% 25.090% 74.91%

No. 16 138 23.7154% 48.8054% 51.2%

No. 30 127.8 21.91% 70.7154% 29.2850%

No. 50 97 16.6695% 87.3849% 12.62%

No. 100 66.8 11.4796% 98.92% 1.08%

Pan <u> 6.3 </u> 1.08% 100% 0%

581.9 gram

Effective size = percentage finer 10% ( $$$D_{20}$ )

0.149 mm, N 100, % finer 1.08

0.297, N 50 , % finer 12.62%

x , 10%

$y-1.08 = \frac{12.62 - 1.08}{0.297 - 0.149}(x-0.149)$

$(10-1.08) \times \frac{0.297 - 0.149}{12.62 - 1.08}+ 0.149=x$

x = 0.2634 mm

Effective size, $D_{10} = 0.2643 \ mm$

Now, N 16 (1.19 mm) , 51.2%

N 8 (2.38 mm) , 74.91%

x, 60%

$60-51.2 = \frac{74.91-51.2}{2.38-1.19}(x-1.19)$

x = 1.6317 mm

$\therefore D_{60} = 1.6317 \ mm$

Uniformity co-efficient = $\frac{D_{60}}{D_{10}}$

$Cu= \frac{1.6317}{0.2643}$

Cu = 6.17

Now, fineness modulus = $\frac{\Sigma \text{\ cumulative retain on all sieve }}{100}$

$=\frac{\Sigma (10.225+25.09+48.8054+70.7165+87.39+98.92+100)}{100}$

= 4.41

which lies between No. 4 and No. 5 sieve [4.76 to 4.00]

So, fineness modulus = 4.38 mm

7 0

3 years ago

(TCO 1) Name one disadvantage of fixed-configuration switches over modular switches. a. Ease of management b. Port security b. F

frutty [35]

Answer:

The answer is A.

Explanation:

Two main types of network switches, modular and fixed configuration switches, are used for connecting the devices with one another provided they are on the same network.

As the name suggests, modular switches can be configured according to your needs and specific situations where you need a different setup.

The one advantage fixed-configuration switches have over the modular switches is that they are easier to operate. You can't change anything for a different application but they are simpler to setup and use, you can just plug them in and start using. They are usually for the more casual end-user and home networks etc.

I hope this answer helps.

5 0

3 years ago

The development of various technologies led to many historic events. Use information from the Internet to describe one major his

11111nata11111 [884]

Answer:

1. Industrial revolution was initiated or borne through the production of Steel

2. World War 1 led to the development of Tanks

Explanation:

The production of Steel through the Bessemer Process in the middle of the nineteenth century was a major technological development that spurred the Industrial revolution. This invention led to the widespread use of steel in the production of many things including vehicles and airplanes.

During the First World War in 1914, soldiers found the use of just their armaments in battle as not so productive. This led to the development of Tanks in 1915 that would continue moving towards the enemy even when being shot at.

4 0

3 years ago

You are considering purchasing a compact washing machine, and you have the following information: The Energy Guide claims an est

RSB [31]

Answer: $15.34

Explanation: see image below

8 0

3 years ago