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3 years ago

I gave 15 min to finish this java program

Engineering

1 answer:

lisov135 [29]3 years ago

4 0

Answer:

class TriangleNumbers

{

public static void main (String[] args)

{

for (int number = 1; number <= 10; ++number) {

int sum = 1;

System.out.print("1");

for (int summed = 2; summed <= number; ++summed) {

sum += summed;

System.out.print(" + " + Integer.toString(summed));

}

System.out.print(" = " + Integer.toString(sum) + '\n');

}

Explanation:

We need to run the code for each of the 10 lines. Each time we sum numbers from 1 to n. We start with 1, then add numbers from 2 to n (and print the operation). At the end, we always print the equals sign, the sum and a newline character.

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g a heat engine is located between thermal reservoirs at 400k and 1600k. the heat engine operates with an efficiency that is 70%

Bond [772]

Answer:

Heat rejected to cold body = 3.81 kJ

Explanation:

Temperature of hot thermal reservoir Th = 1600 K

Temperature of cold thermal reservoir Tc = 400 K

efficiency of the Carnot's engine = 1 - $\frac{Tc}{Th}$

eff. of the Carnot's engine = 1 - $\frac{400}{600}$

eff = 1 - 0.25 = 0.75

efficiency of the heat engine = 70% of 0.75 = 0.525

work done by heat engine = 2 kJ

eff. of heat engine is gotten as = W/Q

where W = work done by heat engine

Q = heat rejected by heat engine to lower temperature reservoir

from the equation, we can derive that

heat rejected Q = W/eff = 2/0.525 = 3.81 kJ

6 0

3 years ago

Consider an open loop 1-degree-of-freedom mass-spring damper system. The system has mass 4.2 kg, and spring stiffness of 85.9 N/

Marat540 [252]

Answer:

Damping ratio $\zeta =0.0342$

Explanation:

Given that

m=4.2 kg,K=85.9 N/m,C=1.3 N.s/m

We need to find damping ratio

We know that critical damping co-efficient

$C_c=2\sqrt {mk}$

$C_c=2\sqrt {4.2\times 85.9}$

$C_c=37.98$ N.s/m

Damping ratio( $\zeta$ ) is the ratio of damping co-efficient to the critical damping co-efficient

So $\zeta =\dfrac{C}{C_c}$

$\zeta =\dfrac{1.3}{37.98}$

$\zeta =0.0342$

So damping ratio $\zeta =0.0342$

3 0

4 years ago

Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output tho

Likurg_2 [28]

Answer:

See explanation

Explanation:

//Include the

//required header files.

#include <stdio.h>

//Define the

//main() function.

int main(void) {

//Declare the

//required variables.

char input_char;

int input_int;

double input_double;

char input_string[100];

//Prompt the user

//to enter an integer.

printf("Enter integer: ");

//Read and store

//the integer.

scanf("%d", &input_int);

//Prompt the user

//to enter a double value.

printf("Enter double: ");

//Read and store

//the double value.

scanf("%lf", &input_double);

//Prompt the user

//to enter a character.

printf("Enter character: ");

//Read and store

//the character.

scanf(" %c", &input_char);

//Prompt user to

//enter the string

printf("Enter string: ");

//Read and

//store the string.

scanf("%s", input_string);

//(1)

//Display the values.

printf("%d %lf %c %s\n",

input_int, input_double,

input_char, input_string);

//(2)

//Display the values

//in reverse order.

printf("%s %c %lf %d\n",

input_string, input_char,

input_double, input_int);

//(3)

//Cast the double to

//an integer and display it.

printf("%lf cast to an integer is %d",

input_double, (int)(input_double));

//Return from the

//main() function.

return 0;

}

4 0

3 years ago

A stainless steel ball (rho = 8055 kg/m3, cp = 480 J/kg·K) of diameter D = 0.21 m is removed from the oven at a uniform temperat

Nataliya [291]

Answer:

Explanation:

The complete detailed explanation which answer the question efficiently is shown in the attached files below.

I hope it helps a lot !

5 0

3 years ago

Read 2 more answers

The blade tension is correct when you can hear a O Thunk O Twang O Neither

Anastaziya [24]

Answer:

maybe it's twang because of the blade tension

3 0

3 years ago