Answer:
Cost = $2527.2 per month.
Explanation:
Given that
Discharge ,Q = 130 L/min
So

Cost = $0.45 per cubic meter
1 month = 30 days
1 days = 24 hr = 24 x 60 min
1 month = 30 x 24 x 60 min
1 month = 43,200 min
Lets x
x = 0.13 x 43,200

So the total cost = 5616 x 045 $
Cost = $2527.2 per month.
Answer:
Constellations
Explanation:
Constellations describes a group of stars that appear to form a pattern or a picture. Example of common patterns are : Leo the Lion or Orion the Great Hunter. It is easy to recognize constellations and most people will tend to orient with these patterns. There are 88 patterns currently known.
Answer:
The speed is the same at 1.5 m/s while
The work done by the force F is 0.4335 J
Explanation:
Here we have angular acceleration α = v²/r
Force = ma = 2.8 × 1.5²/r₁
and ω₁ = v₁/r₁ = ω₂ = v₁/r₂
The distance moved by the force = 600 - 300 = 300 mm = 0.3 m
If the velocity is constant
The speed is 1.5 m/s while the work done is
2.8 × 1.5²1/(effective radius) ×0.3
r₁ = effective radius
2.8*9.81 = 2.8 × 1.5²/r₁
r₁ = 0.229
The work done by the force = 2.8 × 1.5²*1/r₁ *0.3 = 0.4335 J
Answer:
Answer for the question:
Given a 8-bit ripple carry adder and the following four input scenarios: (i) A4 + 1F, (ii) AB+55, (iii) CA+34, (iv) 6D+29. a) Under which input scenario can adder generate correct output with the minimal delay? b) Under which input scenario can adder generate correct output with the maximum delay?
Is given in the attachment.
Explanation:
Answer:
- for i in range(0,11):
- print("Number: " + str(i) + " | Multiplied by 2: " + str(i * 2) + " | Multiplied by 10: " + str(i*10))
Explanation:
Firstly, create a for loop (Line 1). Since we intend to print 0 through 10, we need values 0 and 11 as parameters of range function. The range(0,11) will create a range of values 0 - 10 (11 not inclusive). The for loop will iterate through the range of values 0 - 11 one by one and then print the original value followed by value multiplied by 2 and also the value multiplied by 10 (Line 2).