Answer: Its average atomic mass is 114.9 amu
Explanation:
Mass of isotope 1 = 113 amu
% abundance of isotope 1 = 5% = 
Mass of isotope 2 = 115 amu
% abundance of isotope 2 = 95% = 
Formula used for average atomic mass of an element :
![A=\sum[(113\times 0.05)+(115\times 0.95)]](https://tex.z-dn.net/?f=A%3D%5Csum%5B%28113%5Ctimes%200.05%29%2B%28115%5Ctimes%200.95%29%5D)
Thus its average atomic mass is 114.9 amu
Answer:
a. more than the earth pull on the moon sorry if false
Answer:
Explanation:
A homogeneous mixture consists of one single phase while a heterogeneous mixture consists of two or more phases.
Answer:
0.78× 10 ²³ molecules
Explanation:
Given data:
Mass of pyridine = 10.35 g
Number of molecules = ?
Solution:
Number of moles of pyridine:
Number of moles = mass/molar mass
Number of moles = 10.35 g/ 79.1 g/mol
Number of moles = 0.13 mol
Number of molecules;
1 mole contain 6.022× 10 ²³ molecules
0.13 mol × 6.022× 10 ²³ molecules / 1mol
0.78× 10 ²³ molecules
