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malfutka [58]
3 years ago
10

When does radioactive decay occur

Physics
1 answer:
castortr0y [4]3 years ago
8 0

Answer:

C.when the nucleus decays

Explanation:

In chemical reactions, the outermost electrons of atoms are re-arranged somehow without the involvement of the nuclei of the participating atoms of the elements.

Nuclear reactions causes changes within the atomic nucleus. For every atomic nucleus, a specific neutron/proton ratio ensures stability. When the stability ratio differs an atom becomes unstable and splits into one or more other nuclei with the emission of small particles of matter. This is what radioactivity entails.

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Which purpose does a light bulb serve in a circuit?
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A light bulb is that component of circuit that lights up when electricity flows through it and vice versa. Its main function is to tell whether electricity is being supplied or not. Its function is also to light up dark places.

Explanation:

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2 years ago
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When an object absorbs light energy, it reflects
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I’m pretty sure it’s C
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How do i write newton's second law for parallel directions
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Just copy and paste

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True or False: The northern & southern lights are caused by solar wind particles interacting with gases in our atmosphere.
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False.

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4 0
3 years ago
Force F = (-6.0 N)ihat + (2.0 N) jhatacts on a particle with position vector r =(4.0 m) ihat+ (4.0 m) jhat.
finlep [7]

Answer:

\tau=(-32k)\ N-m

\theta=116.55^{\circ}

Explanation:

Given that.

Force acting on the particle, F=(-6i + 2.0j)\ N

Position of the particle, r=(4i+4j)\ m

To find,

(a) Torque on the particle about the origin.

(b) The angle between the directions of r and F

Solution,

(a) Torque acting on the particle is a scalar quantity. It is given by the cross product of force and position. It is given by :

\tau=F\times r

\tau=(-6i + 2.0j)\times (4i+4j)

\tau=\begin{pmatrix}0&0&-32\end{pmatrix}

\tau=(-32k)\ N-m

So, the torque on the particle about the origin is (32 N-m).

(b) Magnitude of r, |r|=\sqrt{4^2+4^2}=5.65\ m

Magnitude of F, |F|=\sqrt{(-6)^2+2^2}=6.324\ m

Using dot product formula,

F{\circ}\ r=|F|.|r|\ cos\theta

cos\theta=\dfrac{F{\circ} r}{|F|.|r|}

cos\theta=\dfrac{-24+8}{6.324\times 5.65}

\theta=116.55^{\circ}

Therefore, this is the required solution.

6 0
2 years ago
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