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mojhsa [17]
3 years ago
5

If solution A has twice as much solute as solution B is it possible for them to have the same concentration

Chemistry
1 answer:
zalisa [80]3 years ago
6 0
The masses of solute in the 2 solutions can be different but result in the same concentration, this is best explained with examples. 
Say solution A contained 10g of solute and had a volume of 100dm^3
If solution B contained 5g of solute and had a volume of 50dm^3 this would make the concentrations of A and B identical.

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Calculate the molarity of 0.700 mol of na2s in 1.05 l of solution.
slamgirl [31]
Molarity is the amount of solute molecule (in moles) per 1L of solvent. In this case, the solute is 0.7mol Na2S and the solvent volume is 1.05L. Since the unit in this problem is already mol and L then you don't need to do any conversion of the units. The calculation would be:

molarity = mol of solute / (1L/ volume of solvent)
molarity = 0.7 mol/ (1L/ 1.05L)= 0.67M
6 0
3 years ago
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Answer:

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Explanation:

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3 years ago
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Read 2 more answers
Can somebody Answer number 23 please it’s for a exam
qaws [65]

Answer:

I think everything that's there is correct.

Explanation:

Bleach with pH of about 12.5 would be a strong base.

Milk with pH of 6.5 and Blood with pH around 7 would be neutral.

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8 0
3 years ago
A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°c. what is the magnitude of k at 75.0°c if ea =
IgorC [24]
According to this formula:
K= A*(e^(-Ea/RT) when we have K =1.35X10^2 & T= 25+273= 298K &R=0.0821
Ea= 85.6 KJ/mol So by subsitution we can get A:
1.35x10^2 = A*(e^(-85.6/0.0821*298))
1.35x10^2 = A * 0.03
A= 4333
by substitution with the new value of T(75+273) = 348K & A to get the new K
∴K= 4333*(e^(-85.6/0.0821*348)
  = 2.16 x10^2
8 0
3 years ago
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