From the mole ratio of the reaction as given in the equation of the reaction, the mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is 310.245 g.
<h3>What mass of calcium chloride can be produced from 5.59 mol of hydrochloric acid?</h3>
The mass of calcium chloride that can be produced from 5.59 mol of hydrochloric acid is determined from the equation of the reaction.
The equation of the reaction is given below:
Ca²⁺ (aq) + 2 HCl (aq) ---> CaCl₂ (s) + H₂ (g)
From the equation of the reaction, the mole ratio of HCL and calcium chloride is 2 : 1
Therefore, moles of calcium chloride that can be produced will be:
The moles of calcium chloride = 5.59 moles * 1/2
The moles of calcium chloride = 2.795 moles
The mass of calcium chloride produced = moles * molar mass
Molar mass of calcium chloride = 111 g/mol
Mass of calcium chloride produced = 2.795 * 111
Mass of calcium chloride produced = 310.245 g
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The iron (III) has 5 valence electrons and the complex is in a octahedral geometry. Since water as a ligand has a small splitting energy, the complex will be a high spin and all of the five electrons will be unpaired.
Answer:
ion-dipole
Explanation:
Let us remember that the potassium cation is an ion, a positive ion to be precise.
There is a dipole existing in the hydrogen cyanide molecule. The positive end of the dipole is on hydrogen while the negative end of the dipole is on the cyanide moiety.
The only possible interaction between the potassium cation and the hydrogen cyanide is an ion dipole interaction. The cation interacts with the cyanide moiety having a partial negative charge in the molecule.
