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Komok [63]
3 years ago
9

Electromagnetic energy travels through space in the form of

Chemistry
1 answer:
GuDViN [60]3 years ago
3 0
Electrons , Or Vibrating Particles
You might be interested in
A. Identify which sets of quantum numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,ms).
Butoxors [25]

Answer:

a. Values are - (1) 3,1,-1,1/2        (2) 2,1,-1,-1/2       (3) 3,0,0,1/2    (4) 4,3,3,-1/2

(5) 3,2,2,1/2

b. Order be- I > Sn > Xe

Explanation:

a.

Valid quantum numbers are -

'l' value should be less than 'n' value and 'ml' value should be '-l' to 'l'

'ml' value should not more than 'l' or 'n'.

Values are -

3,1,-1,1/2

2,1,-1,-1/2

3,0,0,1/2

4,3,3,-1/2

3,2,2,1/2

b.

Given that-

I [Kr]4d¹⁰5s²5p⁵

Sn [Kr]4d¹⁰5s²5p²

Xe [Kr]4d¹⁰5s²5p⁶

Order be-

I > Sn > Xe

Xe is least because it is completely filled outer shell (5s²5p⁶

4 0
3 years ago
What are the groups on the periodic table let us predict how elements will react
cluponka [151]

Answer:

The vertical columns are called groups.

Explanation:

Periodic table consist of vertical columns and horizontal rows.

Vertical columns are called groups while horizontal rows are called periods.

There are seven periods and 18 groups in periodic table.

The elements in same group have similar properties and can react in a similar way.

The elements in same group have same number of valance electrons that's why their reactivity is same.

Consider the example of alkaline earth metals. They are present in group two and have same number of valance electrons (two valance electrons).

They react with oxygen and form oxide.

2Ba   +   O₂   →    2BaO

2Mg  +   O₂   →    2MgO

2Ca +   O₂   →    2CaO

this oxide form hydroxide when react with water,

BaO  + H₂O   →  Ba(OH)₂

MgO  + H₂O   →  Mg(OH)₂

CaO  + H₂O   →  Ca(OH)₂

With sulfur,

Mg + S   →  MgS

Ca + S   →  CaS

Ba + S   →  BaS

7 0
3 years ago
What is the amount in moles of a 52 g sample of aluminium fluoride, AIF3
Karo-lina-s [1.5K]

Answer:

Try looking for some kind of answer that has to do with .61904

Explanation:

52 g x 1 mol/ (molar mass of aluminum fluoride) 84 g = .619047619

Sorry if this is wrong but that's my best guess

6 0
2 years ago
What is the charge of an atom after it gains an electron during the formation of a bond?
Alex_Xolod [135]

Answer:

<em>D. One negative charge</em>

Explanation:

During the formation of a bond, if an atom gains an electron, after that it will be left with a negative charge compared to the atom before the bond is formed. This is because in these types of bonds, which are <em>ionic bonds</em>, there is a <em>transfer of electrons between atoms</em>, there will be one or more atoms that yield electrons that will be captured by another and other atoms that gain them, and the difference of charges produced by this transfer of electrons, will cause the union to occur due to the attraction between electrostatic forces.

If you have a neutral atom before joining, and it gains an electron to form a bond,<em> it will have one electron more than its initial state</em> (in the initial state, the number of protons and electrons is the same, because the atoms they are electrically neutral), so having an extra electron will make it have a negative charge, since there will be a difference between the number of protons and electrons that the atom possesses. <em>This is why the correct answer is D. </em>

In the case of <em>response A and B</em>, <em>the atom could only remain positively charged if it loses electrons</em>, but as in this case it wins, <em>they are not correct</em>.

<em>The answer C is also not correct</em> because only one electron wins, so that it is left with two negative charges, <em>it should gain two electrons during the bond formation.</em>

7 0
3 years ago
after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2
Alexxandr [17]
Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
 the number of the mol solute

22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3&#10;&#10;2) 725 ml = 0.725 L&#10;&#10;&#10;

3) Molarity = \frac{number/ mol/solute}{Volume/solution} = \frac{0.129}{0.725} &#10;&#10;

Molarity= \frac{0.178 mol}{L} , &#10;&#10;or 0.178 M&#10;


3 0
3 years ago
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