The spider is traveling in a circle with radius = 15cm
The circumference of any circle = <em>2 pi (radius)</em>
The circumference of the spider's path = 2 pi (15 cm) = 30 pi cm
The spider completes a trip around this path 78 times per minute.
Its speed, relative to you, is
(78) x (30 pi) cm/min =
2,340 pi cm/min = 7,351.33 cm/min =
<em> 73.5133 meter/min =</em>
<em>4.411 km/hr =</em>
<em>2.74 miles/hour
</em>(After the last appearance of pi,
all numbers are rounded.)<em>
</em>
Answer:
they require a medium
Explanation:
your welcome.............
Answer:
number of cycles = 4.68 × 10⁴ cycles
Explanation:
In damped RLC oscillation
voltage (V(t)) = V_o\ e^{-\dfrac{tR}{2L}}............(1)
given,
C = 0.17μF = 0.17 × 10⁻⁶ F
R = 1.4 Ω
L = 15 m H = 15 × 10⁻³ H V(t) = V₀/2
From the equation (1)


taking log both side



t = 14.85 sec
time period


T = 3.172 × 10⁻⁴
number of cycle =
= 
number of cycles = 4.68 × 10⁴ cycles
Answer:
acceleration= force / mass
a= 1.48 m/sec^2