Answer:
Hello the options to your question is missing attached below are the missing options
- Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical
- The electric forces are equal in this case because both balloons had the same amount of electric charge
Answer :
Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical
Explanation:
The Balloons have the same amount of force exerted on them, because Electrical forces are symmetrical, The electric repulsion of the Balloons is equal because electric forces between two objects are always symmetrical, therefore the two Balloons are deflected to the same angle
Answer:
No, it is not attracted.
Explanation:
If any sphere is electrically neutral it is not attracted. The materials which are attracted by magnet are called magnetic material whereas which are not attracted are called non magnetic material. Sphere made up of non magnetic materials such as glass, wood, paper will not attracted weather is kept near north pole or near south pole.
Answer:
Explanation:
The combined wave only end up been more powerful than the Longitudinal wave. This means, the transverse wave is more powerful than the combined wave. In transverse wave, the oscillation is perpendicular to the direction of the wave, while in longitudinal wave, the motion of the movement of the object is parallel to the movement of the wave. And in combined wave, the movement of the medium is in a circular manner,
Different layers represent clouds made of gases that condense at different temperatures.
Explanation:
It is given that,
Mass of an object, ![m=4\times 10^5\ kg](https://tex.z-dn.net/?f=m%3D4%5Ctimes%2010%5E5%5C%20kg)
(a) Time period of oscillation, T = 2.4 s
The formula for the time period of spring is given by :
![T=2\pi \sqrt{\dfrac{m}{k}}](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7B%5Cdfrac%7Bm%7D%7Bk%7D%7D)
Where
k is the force constant
![k=\dfrac{4\pi ^2 m}{T^2}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7B4%5Cpi%20%5E2%20m%7D%7BT%5E2%7D)
![k=\dfrac{4\pi ^2 \times 4\times 10^5}{(2.4)^2}](https://tex.z-dn.net/?f=k%3D%5Cdfrac%7B4%5Cpi%20%5E2%20%5Ctimes%204%5Ctimes%2010%5E5%7D%7B%282.4%29%5E2%7D)
![k=2.74\times 10^6\ N/m](https://tex.z-dn.net/?f=k%3D2.74%5Ctimes%2010%5E6%5C%20N%2Fm)
(b) Displacement in the spring, x = 2.2 m
Energy stored in the spring is given by :
![U=\dfrac{1}{2}kx^2](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7Dkx%5E2)
![U=\dfrac{1}{2}\times 2.74\times 10^6\ N/m\times (2.2\ m)^2](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202.74%5Ctimes%2010%5E6%5C%20N%2Fm%5Ctimes%20%282.2%5C%20m%29%5E2)
![U=6.63\times 10^6\ J](https://tex.z-dn.net/?f=U%3D6.63%5Ctimes%2010%5E6%5C%20J)
Hence, this is the required solution.