Answer:
The expression for the period of the pendulum is
T=2π√l/g
Explanation
Kindly find attached document for the analysis of the pendulum and the derivation for the period
What is a simple harmonic motion?
Simple harmonic motion is defined as the to and fro motion of an object or a particle whose acceleration is directly proportional to its displacement from a fixed point and is always directed towards that point.
Answer:
,
(before collision),
(after collision).
Explanation:
The total momentum is obtained using the Principle of Momentum Conservation:

It is trivial to find that final speed and total momentum of the system are zero:

The total kinetic energy of the system becomes zero due to the inellastic collision and the same masses and speeds. Total kinetic energies before and after collision are, respectively:


Answer:
decreases, but frequency increases.
Explanation:
Wavelength and frequency are inversely proportional, meaning the higher the frequency, the shorter the wavelength, and the lower the frequency, the longer the wavelength.
Answer:
b. 40 degrees
Explanation:
Range = (U²Sin2tita)/g
Let's assume a constant velocity of 1 m/s and acceleration of 10 m/s² and try the following angles.
For 10 degree
Range= (sin20)/10
Range = 0.034m
For 40 degrees
Range= sin80/10
Range = 0.098m
For 70 degrees
Range = sin140/10
Range = 0.064
For 90 degrees
Range = sin180/10
Range = 0
Comparing the above result, we can see the degree with the highest range is degree 40.
Answer:
h = 5.38 10¹⁶ m
Explanation:
Let's start this exercise by assuming that all the potential energy of the electron is converted into kinetic energy, let's use the conservation of energy
starting point. Just before ionization
Em₀ = U = qE
final point. Right after ionization
Em_f = K = ½ m v²
Energy is conserved
Em₀ = Em_f
q E = ½ m v²
v² = 2qE / m
Now we can use the relationship between net work and kinetic energy
W_net = ΔK
net work is the work done by the electron minus the binding energy with the atom, called the work function, Ф = 3 10-19 J
W - Ф = K_f - K₀
we assume that the electron converts all its initial initial kinetic energy to be zero
W -Ф = ½ m v² - 0
W = ½ m v² +Ф
we substitute
W = 1/2 m 2qE/m + E
W = qE +Ф
W = 1.6 10⁻¹⁹ 3 10⁶ + 3 10⁻¹⁹
W = 4.8 10⁻¹³ + 3 10⁻¹⁹
W = 4.8 10⁻¹³ J
When the electron is in air, its kinetic energy can be transformed into gravitational potential energy
As the electron is in the air, all work is transformed into scientific energy
W = K
starting point Em₀ = K = W
end point Em_F = U = m g h
energy conservation Em₀ = Em_f
W = m g h
h =
let's calculate
h =
h = 5.38 10¹⁶ m