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Anastaziya [24]
3 years ago
15

Design a PD compensator for the following system to reduce the settling time by a factor of 4 while continuing to operate the sy

stem with a 20.5% overshoot. State your final compensator and gain. What can you say about a 2nd order approximation. Simulate the uncompensated and compensated step response:

Engineering
1 answer:
Helen [10]3 years ago
5 0

Answer:

Hello your question lacks the required diagram attached below is the missing diagram

final compensator = k ( s + 9.3731 )

gain = 695.4275

Explanation:

attached below is the remaining part of the detailed solution of the question

C(s) = \frac{k}{s(s+8)(s+25) }   The dominant poles fn 20.5% are at Sd = -2.91 + 5.77 J

uncompensated system setting time (ts) = 4/2.91 = 1.3746

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How could increasing the budget for testing have prevented the problem experienced by the mars orbiter?
vlada-n [284]

Answer:

this might help

Explanation:

https://science.ksc.nasa.gov/mars/msp98/misc/MCO_MIB_Report.pdf

5 0
3 years ago
S1.1 The Acre-Foot. Hydraulic engineers in the United States often use, as a unit of volume of water, the acre-foot, defined as
Mars2501 [29]

Answer:

1072 acre foot

1331424000 kg

Explanation:

1 feet has 12 inches, so 2 in is 0.167 feet.

1 km^2 has 1 million m^2.

1 acre is 4074 m^2.

So, 1 km is 247 acres.

Then 26 km^2 is 6422 acres.

So, the volume of water is

6422 * 0.167 = 1072 acre-foot

Since one cubic meter of water has 1000 kg

One inch is 25.4 mm = 0.0254 m

One feet is 12 * 0.0254 = 0.3048 m

An acre-feet has a volume of

4074*0.3048 = 1242 m^3

And that is a mass of water of

1242 * 1000 = 1242000 kg/acre-feet

Therefore the mass of rainwater in the town is of

1072 * 1242000 = 1331424000 kg = 1331424 tons

4 0
3 years ago
What is the hardware engineering​
a_sh-v [17]

Answer:

Hardware Engineering is the process of designing, developing, testing and producing computer systems and various physical components related to computer systems.

8 0
3 years ago
What does snow fall from?
Klio2033 [76]

Answer:

Clouds

Explanation:

It is created by trapped dust and water.

4 0
3 years ago
A cylindrical buoy is 2m in diameter and 2.5m long and weight 22kN . The specific weight of sea water is 10.25kN/m^3 . (I) Show
aleksandrvk [35]

Answer:

GM

So the bouy does not float with its axis vertical

Explanation:

From the question we are told that:

Diameter d=2m

Length l=2.5m

Weight W=22kN

Specific weight of sea water \mu= 10.25kN/m^3

Generally the equation for weight of cylinder is mathematically given by

Weight of cylinder = buoyancy Force

W=(pwg)Vd

Where

V_d=\pi/4(d)^2y

Therefore

22*10^3=10.25*10^3 *\pi/4(2)^2y\\\\\22*10^3=32201.3247y\\\\\y=1.5m

Therefore

Center of Bouyance B

B=\frac{y}{2}=0.26m\\\\B=0.75

Center of Gravity

G=\frac{I.B}{2}=2.6m

Generally the equation for\BM is mathematically given by

BM=\frac{I}{vd}\\\\BM=\frac{3.142/64*2^4}{3.142/4*2^2*0.5215}\\\\BM=0.479m\\\\

Therefore

BG=2.6-0.476\\\\BG=0.64m

Therefore

GM=BM-BG\\\\GM=0.479m-0.64m\\\\GM=-0.161m\\\\

Therefore

GM

So the bouy does not float with its axis vertical

4 0
3 years ago
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