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Lerok [7]
3 years ago
12

Quadrilateral PAID is a rectangle whose diagonals have the endpoints P(-3, -2)I(4, -7) and A(4, -2)D(-3, -7). Find the diagonals

' intersection point. In complete sentences, explain which method you used for finding the intersection point.
Mathematics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

(0.5,-4.5)

Step-by-step explanation:

The given rectangle has diagonals have the endpoints P(-3, -2) ,I(4, -7) and A(4, -2) ,D(-3, -7)

The diagonals of the rectangle bisect each other so we use the midpoint formula to find their point of intersection.

The midpoint formula is;

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We use any pair of endpoints of the diagonals to find the point of intersection.

Using A(4, -2) ,D(-3, -7)

(\frac{4+-3}{2},\frac{-2+-7}{2})

(\frac{1}{2},\frac{-9}{2})

or

(0.5,-4.5)

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Whats the answer????
Citrus2011 [14]

Step-by-step explanation:

the general slope intercept form is

y = ax + b

a is the slope (and always the factor of x). it is expressed as ratio y/x indicating how many units y changes, when x changes a certain amount of units when going from one point to another.

b is the y-intercept, the y value of the point, where the line crosses the y-axis (in other words : the y value when x = 0).

so, look at the chart. where do we see points with integer coordinates (these are the easiest to read correctly and work with) ?

I see for example (0, -6) and (4, -7).

to go from the first to the second point :

x changes by +4 units (from 0 to 4).

y changes by -1 unit (from -6 to -7).

the slope a is therefore -1/4.

and the first point i picked gives us also automatically the y-intercept (-6).

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5 0
3 years ago
What happens to the distance between each billiard ball during this rigid<br><br> transformation?
Delicious77 [7]

The question is incomplete. Here is the complete question.

To set up a game of billiards, the first player moves the balls contained within a triangular rack as shown. What happens to the distance between each billiard during this rigid transformation?

A. The distance remains constant throughout the transformation.

B. The distance decreases at the start and increases after all motion stops.

C. The distance stays the same at the start but decreasesexactly when motion ends.

D. The distance increases at the start and then decreases as the rack gets further from the player.

Answer: A. The distance remains constant throughout the transformation.

Step-by-step explanation: In a <u>rigid</u> <u>motion</u>, all moving points in the plane are moving in way such tha:

1)  relative distance between them stays the same and

2) relative position of the points stays the same

There are four types of rigid motions: translation, rotation, reflexion and glide reflection.

<u>Translation</u>: every point or object is moved by the same amount and in the same direction;

<u>Rotation</u>: the object rotates by the same amount around a fixed point;

<u>Reflexion</u>: the object exchange points from one side of a line with points on the other side of the line at the same distance from the line;

<u>Glide</u> <u>Reflection</u>: is a mirror reflection followed by a translation parallel to the mirror.

In the game of billiards, because all the balls are inside the triangular rack, the distance, and also the position, between them stays the same, limited by the rack. Since they are moving by the same amount in the same direction, the rigid transformation is a translation.

Therefore, the distance of the balls in the triangular rack remains constant throughout the transformation.

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