Answer:
The volume is increased.
Explanation:
According to <em>Charles' Law</em>, " <em>at constant pressure the volume and temperature of the gas are directly proportional to each other</em>". Mathematically this law is presented as;
V₁ / T₁ = V₂ / T₂ -----(1)
In statement the data given is,
T₁ = 10 °C = 283.15 K ∴ K = 273.15 + °C
T₂ = 20 °C = 293.15 K
So, it is clear that the temperature is being increased hence, we will find an increase in volume. Let us assume that the starting volume is 100 L, so,
V₁ = 100 L
V₂ = Unknown
Now, we will arrange equation 1 for V₂ as,
V₂ = V₁ × T₂ / T₁
Putting values,
V₂ = 100 L × 293.15 K / 283.15 K
V₂ = 103.52 L
Hence, it is proved that by increasing temperature from 10 °C to 20 °C resulted in the increase of Volume from 100 L to 103.52 L.
Answer:
most likely c
Explanation:
the volume is increased by the quickly moving water particles
Answer:
10.1 ms^-2
Explanation:
From;
v = u + at
v = final velocity
u = initial velocity
a= acceleration
t = time taken
To convert the velocity from Km/hr to m/s we us;
x * 1000/3600
Where x is the velocity in Km/hr
So;
799 * 1000/3600 = 221.9 m/s
11325 * 1000/3600 = 3145.8 m/s
4.8 minutes = 4.8 * 60 = 288 s
Applying the formula;
a= v - u/t
a = 3145.8 - 221.9/288
a = 10.1 ms^-2
We are given ΔG°rxn = -30.5 kJ/mol for the following reaction:
ATP + H₂O → ADP + HPO₄²⁻
We are given a series of concentrations for each of the species and are asked to find the value of ΔG for the reaction. We can use the following formula:
ΔGrxn = ΔG°rxn + RTlnQ
We can use R = 0.008314 kJ/molK; T = 335.15 K and Q is the reaction quotient which can be found as follows, and be sure to first convert each concentration of mM to M:
Q = [ADP][HPO₄²⁻]/[ATP]
Q= [0.00010][0.005]/[0.005]
Q = 0.0001
Now we can use the above formula to solve for ΔGrxn.
ΔGrxn = -30.5 kJ/mol + (0.008314)(310.15)ln(0.00010)
ΔGrxn = -54.3 kJ/mol
The value of ΔGrxn = -54.3 kJ/mol.
Answer: The balanced equation is 
.
Explanation:
The given reaction equation is as follows.
Number of atoms present on reactant side are as follows.
- Li = 1
- H = 1
= 1
Number of atoms present on product side are as follows.
- Li = 1
- H = 2
- = 1
To balance this equation, multiply Li by 2 and 
by 2 on reactant side. Also, multiply 
by 2 on product side.
Hence, the equation can be rewritten as follows.
Now, number of atoms present on reactant side are as follows.
- Li = 2
- H = 2
- = 2
Number of atoms present on product side are as follows.
- Li = 2
- H = 2
- = 2
As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.
Thus, we can conclude that the balanced equation is .
