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4 years ago

Round 7.2199 to the nearest thousandth

Mathematics

2 answers:

AleksandrR [38]4 years ago

5 0

the answer i got is 7.2000

borishaifa [10]4 years ago

4 0

7.2199

The bold number is in the thousandth place. So, now look at the right. The number is 9. Now, since theres another 9.... then go to the 1 place. It will be now 7.22

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When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con

maria [59]

First:

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Second:

F=m.a

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3 years ago

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3 years ago

A line includes the points (1, 9) and (0, 5). What is it’s equation in the slope-intercept form?

scoundrel [369]

Equation is y = 4x + 5

Step-by-step explanation:

Step 1: Find the slope of the line by m = (y2 - y1)/(x2 - x1). Here y2 = 5, y1 = 9, x1 = 1 and x2 = 0

⇒ m = (5 - 9)/(0 - 1) = 4

Step 2: Find y-intercept, b. Since the line passes through (0, 5) b = 5
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4 years ago

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UNO [17]

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3 years ago

If for two non-zero vectors a,b : ∣a+b∣=∣a−b∣ then angle between them is:______a. 0b. 45c. 60d. 90

Eddi Din [679]

Answer:

$90^\circ$

Step-by-step explanation:

Given two non zero vectors, $\vec a, \vec b$ .

Let the angle between the two vectors = $\theta$

Given that:

$|\vec a+\vec b|=|\vec a-\vec b|$

Let us have a look at the formula for magnitude of addition of two vectors:

$|\vec x+\vec y|=\sqrt{x^2+y^2+2xycos\theta}$

Where $\theta$ is the angle between the two vectors.

formula for magnitude of subtraction of two vectors:

$|\vec x-\vec y|=\sqrt{x^2+y^2-2xycos\theta}$

As per the given condition:

$\sqrt{a^2+b^2+2abcos\theta}=\sqrt{a^2+b^2-2abcos\theta}$

Squaring both sides:

$a^2+b^2+2abcos\theta=a^2+b^2-2abcos\theta\\\Rightarrow 2abcos\theta=-2abcos\theta\\\Rightarrow cos\theta = -cos\theta\\\Rightarrow 2cos\theta = 0\\\Rightarrow cos\theta = 0\\\Rightarrow \theta = 90^\circ$

So, the angle between the two vectors is: $90^\circ$

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3 years ago