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2 years ago

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12. Since the Clean Air Act was passed in 1970, why is the air still not clean?

1 answer:

maria [59]2 years ago

5 0

Answer:

Congress designed the Clean Air Act to protect public health and welfare from different types of air pollution caused by a diverse array of pollution sources.

Explanation:

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What must happen to an atom of magnesium in order to become a magnesium ion

Zielflug [23.3K]

I would assume that the magnesium would have to come into contact with an ion in order to become a magnesium ion.

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3 years ago

What force is needed to accelerate an object 5 m/s2 if the object has a mass of 10 kg?

Helga [31]

We know, F = m * a
F = 10 * 5
F = 50 N

In short, Your Answer would be 50 Newtons

Hope this helps!

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3 years ago

Sheena took the implicit association test (IAT) and found that she responded faster when ""strong"" words were paired with male

poizon [28]

Answer:

The finding suggests that

Sheena have an implicit belief that men are stronger than women.

Explanation:

Implicit Association Test:

In the field of social psychology, this test is used to determine the power of a person to associate between different objects in an implicit way. For example, are colored people good or bad?

So this test finding suggests that Sheena have an implicit belief that men are stronger than women by checking her response towards strong words.

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3 years ago

A proton is projected in the positive x direction into a region of a uniform electric field E S 5 126.00 3 105 2 i^ N/C at t 5 0

Dafna11 [192]

Answer:

(a). The magnitude of the acceleration of the proton is $5.74\times10^{13}\ m/s^2$

(b). The initial peed of the protion is $2.83\times10^{6}\ m/s$

(c). The time is $0.493\times10^{-7}\ sec$ .

Explanation:

Given that,

Electric field $E=-6.00\times10^{5}i\ N/C$

Time = 5.0 sec

Distance 7.00 cm

(a). We need to calculate the acceleration

Using formula of force

$F=F_{e}$

$ma=qE$

$a=\dfrac{Eq}{m}$

Where, E = electric field

m = mass of proton

q = charge of proton

Put the value into the formula

$a=\dfrac{-6.00\times10^{5}\times1.6\times10^{-19}}{1.67\times10^{-27}}$

$a=-5.74\times10^{13}\ m/s62$

The magnitude of the acceleration of the proton is $5.74\times10^{13}\ m/s^2$

(b). We need to calculate the initial peed

Using equation of motion

$v^2-u^2=2as$

Where, s = distance

Put the value into the formula

$0-u^2=2\times(-5.74\times10^{13})\times7.00\times10^{-2}$

$u=\sqrt{2\times5.74\times10^{13}\times7.00\times10^{-2}}$

$u=2834783.94$

$u=2.83\times10^{6}\ m/s$

The initial peed of the protion is $2.83\times10^{6}\ m/s$

(c). We need to calculate the time interval over which the proton comes to rest

Using formula

$t=\dfrac{u}{a}$

Where, u = initial velocity

a = acceleration

Put the value into the formula

$t=\dfrac{2.83\times10^{6}}{5.74\times10^{13}}$

$t=0.493\times10^{-7}\ sec$

Hence, (a). The magnitude of the acceleration of the proton is $5.74\times10^{13}\ m/s^2$

(b). The initial peed of the protion is $2.83\times10^{6}\ m/s$

(c). The time is $0.493\times10^{-7}\ sec$ .

5 0

3 years ago

Electro-magnets are created by...

mojhsa [17]

Wrapping in insulated wire around a medal with ferromagnetic properties and applying an electric current

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3 years ago