Answer:
center of mass = −0.50 m
Explanation:
given data
mass m1 = 3.04 kg
distance xm = -8 m
mass m2 = 5.61 kg
distance xM = 3.56 m
solution
we get here center of mass for n mass of system that is express as
center of mass =
......................1
but we have only 2 particle system so we will get
center of mass =
.................2
put here value and we will get
center of mass = 
solve it we will get
center of mass = −0.50 m
Answer: It would be 75
Explanation: If your pushing on the floor at a rate of 5 for 15 seconds you would multiply the numbers and get 75
low temp is low ke, momentum eyc ... molecules hit walls withless speed ....low pressure
m₁ = mass of the first object = 3.0 kg
m₂ = mass of the second object = 3.0 kg
r = distance between the first and second object = 1.0 m
G = universal gravitational constant = 6.67 x 10⁻¹¹ N m²/kg²
F = force of gravity between the two objects = ?
according to law of gravitation, force of attraction "F" between two objects m₁ and m₂, placed distance "r" apart is given as
F = G m₁ m₂/r²
inserting the values
F = (6.67 x 10⁻¹¹) (3.0) (3.0)/(1.0)²
F = (6.67 x 10⁻¹¹) (9.0)
F = 60.03 x 10⁻¹¹ N
F = 6.003 x 10⁻¹⁰ N