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IrinaK [193]
3 years ago
10

Which would BEST describes what occurs when a ball is thrown against a wall? A) The ball will not bounce off the wall. B) The ba

ll hits the wall hard enough to bounce off of it. C) The wall is stronger than the ball and neither exerts any forces. D) The ball exerts a force on the wall and the wall exerts a force back.
Physics
2 answers:
natita [175]3 years ago
4 0

The answer is D. If you throw the ball at a wall, the wall will not move. The wall will exert a force on the ball, therefor the ball will bounce backwards.

oee [108]3 years ago
3 0

Answer:

D) The ball exerts a force on the wall and the wall exerts a force back.

Explanation:

Newton's third law of motion states that:

"When an object A exerts a force on another object B, then object B exerts an equal and opposite force on object A"

In this problem, we can identify (for instance) object A with tha ball and object B with the wall. Therefore, if we apply Newton's third law, we get:

The ball (object A) exerts a force on the wall (object B), therefore the wall (object B) exerts an equal and opposite force on the ball (object A). So, option D is the correct one.

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On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max
sesenic [268]

Work done by a given force is given by

W = F.d

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = W_1 = Fdcos\theta

W_1 = 12*5cos15

W_1 = 57.96 J

Now similarly work done by frictional force

W_2 = Fdcos\theta

W_2 = 4*5cos180

W_2= -20 J

Now total work done on sled

W_{net}= W_1 + W2

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3 years ago
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Answer:

The answer should be light or other electromagnetic radiation

Explanation:

Such as x-rays or other things like that.

<em>-Hope This Helps!</em>

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2 years ago
All the bats living in a cave form a _____ of bats in the cave ecosystem.
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7 0
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A hiker begins a trip by first walking 25.0 km southeast from her car. She stops and sets up her tent for the night. On the seco
Sunny_sXe [5.5K]

Answer:

(a)

x_1=17.68km\\y_1=-17.68km\\x_2=20km\\y_2=34.64km

(b) r=41.32km

\alpha =24.23^o

Explanation:

Let us take the north direction to be the positive y-axis and the east to be positive x-axis.

First day:

25.0 km southeast, which implies 45^o south of east. The y-component will be negative and the x-component will be positive.

x_1=25cos45^o=17.68km

y_1=-25sin45^o=-17.68km

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She starts off at the stopping point of last day. This time, both the y- and x-components are positive.

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x=x_1+x_2=(17.68+20)km=37.68km

y=y_1+y_2=(-17.68+34.64)km=16.96km

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r=\sqrt{x^2+y^2}=41.32km

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3 years ago
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2 years ago
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