Answer:
They interact in a lot of ways, prey, predator, etc.
Answer:
Option D
A type I error is making the mistake of rejecting the null hypothesis when it is actually false.
Explanation:
Error type I is usually represented by alpha symbol and type I error entail making a mistake of rejecting the null hypothesis when it's actually true. Type II error on the other side involves making a mistake of failing to reject null hypothesis when it is actually false. The statement in option D is false because it contradicts the definition of type I error above hence the only false statement in relation to hypothesis testing is option D, A type I error is making the mistake of rejecting the null hypothesis when it is actually false.
Answer:
Because some of the energy is dissipated in the metabolic activities such as digestion and maintaining the warmth of the body of the organism at each level.
Explanation:
Food chain is the sequential chain of energy transfer from one onrgaanism at a trophic level to another organism at the other trophic level. Autotrophs receive the energy from the sun and prepare their own food. Autotrophs then get consumed by the primary heterotrophs and further primary heterotrophs by the secondary heterotrophs. When the secondary heterotrophs die they are then consumed by the scavangers and decayed by the micro-organisms in to the soil which finally help the autotrophs (plants) in their growth.
At each trophic level of the food chain the energy does not gets completely transferred because the organisms also spend some energy in search of the food and the processing of food is also an energy consuming process.
The energy is also used in combating the climatic conditions and predators for the survival.
Answer:
<em>The mass of the shotput is 7.37 Kg.</em>
Explanation:
<u>Mechanical Force</u>
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object. If the net force is zero, the object keeps moving at the same speed or keeps at rest (v=0).
A force of 140 N is exerted by a shot-putter on a shotput, which gets an acceleration of 19 m/s^2. We are required to calculate the mass of the shotput.
It can be done by solving the equation for m:
Substituting the given values:
m = 7.37 Kg
The mass of the shotput is 7.37 Kg.
M = 600 kg
u = 0 (as the car was at rest initially)
v = 5 m/s
Initial kinetic energy = ½mu²
= ½×600×0
= 0
Final kinetic energy = ½mv²
= ½×600×25
= 7500 J