If a force of 40 N does 600 joules of work, then it must have been applied continuously through a distance of (600/40) = 15 meters .
We can't tell how far the object ultimately moved, because we don't know
what other forces may have been acting on it. If there were NO other forces,
then it just kept going, even after the 40-N force stopped, with the same
600 joules of kinetic energy that it got from the work that the force did.
B. It measures <span>changes in the variable that is being controlled
</span>The receptor senses environmental stimuli, sending the information to the integrating center.
Answer:
Using
Period ( P) is given as
P~√(L/g).
a) since mass has no effect on the period of a pendulum. So, the period will remain 1.8seconds
b) using the formula above ,period varies with the square root of the length. Thus , when the length doubles, the period is multiplied by √2. So, the period is 1.8s*√2 = 2.54s
c) in this case, the period is multiplied by √(1/2).
1.8√(1/2)=1.27s.
d) amplitude of the pendulum doesn't affect the period (unless itsvery high, so, the period is still 1.8s
