Newtons first law of motion is also called galelios law of_______?
2 answers:
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A) -2.0 m
Look at the ray diagram attached in the picture, where:
p identifies the location of the object
q identifies the location of the image
F identifies the focus of the mirror
Each tick represents 1 m
We have
p = 6.0 m is the distance of the object from the mirror
f = -3.0 m is the focal length
From the ray diagram, we see that q has a distance of 2.0 m from the mirror, and it's on the other side of the mirror compared to the object, so
q = -2.0 m
This can also be verified by using the mirror equation:
B) Upright and virtual
As we see from the picture, the image is upright, since it has same orientation as the object.
Also, we notice that the image is on the other side of the mirror, compared to the object. For a mirror,
- An image is said to be real if it is on the same side of the object
- An image is said to be virtual if it is on the opposite side of the mirror
Therefore, this means that the image is virtual.
Answer:
Explanation:
From the question;
We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.
We are to calculate the following task, i.e. to determine the electric field at the distances:
a) at 4.75 cm
b) at 20.5 cm
c) at 125.0 cm
Given that:
the charge (q) = 33.3 nC/m
= 33.3 × 10⁻⁹ c/m
radius of rod = 5.75 cm
a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.
Then, the electric field will be zero.
b) The electric field formula
E = 1461.95 N/C
c) The electric field E is calculated as:
E = 239.76 N/C