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Cloud [144]
3 years ago
5

A 12-inch object is placed 30 inches in front of a plane mirror. A ray of light from the object strikes the mirror at a 45-degre

e angle. How tall is the image produced by the mirror? 12 inches 30 inches 24 inches 45 inches
Physics
2 answers:
dsp733 years ago
5 0

Answer: The correct answer is 12 inches.

Explanation:

Image is formed in the plane mirror:

  • Image formed by the plane mirrors is of same size and shape as that of the object .
  • Distance between the image formed and the mirror is equal to the distance between the object and mirror.

According to question the the height of the image formed in the plane mirror will be of same height as that of the object that is 12 inches.

Hence, the correct answer is 12 inches.

Darya [45]3 years ago
3 0
I think it's 12 inches. Hope it's right.
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Vector ????⃗ has a magnitude of 16.6 and is at an angle of 50.5∘ counterclockwise from the +x‑axis. Vector ????⃗ has a magnitude
natka813 [3]

Answer:

For vector u, x component = 10.558 and  y component =12.808

unit vector = 0.636 i+ 0.7716 j

For vector v, x component = 23.6316 and y component = -6.464

unit vector = 0.9645 i-0.2638 j

Explanation:

Let the vector u has magnitude 16.6

u makes an angle of 50.5° from x axis

So u_x=ucos\Theta =16.6\times cos50.5=10.558

Vertical component u_y=usin\Theta =16.6\times sin50.5=12.808

So vector u will be u = 10.558 i+12.808 j

Unit vector u=\frac{10.558i+12.808j}{\sqrt{10.558^2+12.808^2}}=0.636i+0.7716j

Now in second case let vector v has a magnitude of 24.5

Making an angle with -15.3° from x axis

So horizontal component v_x=vcos\Theta =24.5\times cos(-15.3)=23.6316

Vertical component v_y=vsin\Theta =24.5\times sin(-15.3)=-6.464

So vector v will be 23.6316 i - 6.464 j

Unit vector of v =\frac{23.6316i-6.464}{\sqrt{23.6316^2+6.464^2}}=0.9645i-0.2638j

8 0
2 years ago
Using the rules for the significant figures what do you get when you add 24.545 and 307.3
Tamiku [17]
1
2 4. 5 4 5
+3 0 7. 3 0 0
——————
3 3 1 8 4 5
line up the decimal points and add.
hope this helps!
4 0
3 years ago
Imagine a place in the cosmos far from all gravitational and frictional influences. Suppose that you visit that place (just supp
xz_007 [3.2K]
The rock will continue to travel in a straight line with a constant velocity for ever... The reason is, once it leaves your hand there is no force acting on the rock, so it will just continue to move in a natural motion which is constant velocity.
6 0
3 years ago
The zone of earthquakes and volcanoes surrounding the pacific ocean is called
gulaghasi [49]

Answer:

The Ring of Fire

Explanation:

The ring of fire is also called the Circum-Pacific Belt, it is a path along the pacific ocean consisting of active volcanoes and frequent earthquakes.

It has a length of approximately 40,000 kilometers. It lies on the edge of tectonic plates where the in-earth vibrations and geothermal energies are prone to erupt out.

Ring of fire inhibits about 75% o the earth's volcanoes and 95% of earthquakes occur in this region.

3 0
3 years ago
What is the wavelength of a wave with a frequency of 466 Hz and a speed of
Volgvan

Answer:

<h3>The answer is option B</h3>

Explanation:

The wavelength of a wave can be found by using the formula

\lambda =  \frac{c}{f} \\

where

c is the speed of the wave

f is the frequency

From the question

c = 343 m/s

f = 466 Hz

We have

\lambda =  \frac{343}{466} \\  =  0.73605150...

We have the final answer as

<h3>0.74 m</h3>

Hope this helps you

4 0
2 years ago
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