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The two displacement functions are
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s
The distance between the two objects is
x = x₁ - x₂
= 4t + 161 - 48t + 4t²
x = 4t² - 44t + 161
Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
= 4[ (t - 5.5)² - 5.5² ] + 161
x = 4(t-5)² + 40
Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.
Answer: The distance of the closest approach is 40 m.
x₁ = 4t
x₂ = -161 + 48t - 4t²
where
x₁, x₂ are in meters
t is time, s
The distance between the two objects is
x = x₁ - x₂
= 4t + 161 - 48t + 4t²
x = 4t² - 44t + 161
Write this equation in the standard form for a parabola.
x = 4[t² - 11t] + 161
= 4[ (t - 5.5)² - 5.5² ] + 161
x = 4(t-5)² + 40
Ths is a parabola that faces up and has its vertex (lowest point) at (5, 40).
Therefore the closest approach of the two objects is 40 m.
The graph of x versus t confirms the result.
Answer: The distance of the closest approach is 40 m.
Answer:
A)What average intensity does a GPS receiver on the ground, directly below the satellite, receive? = 9.75 x 10 ∧-15w/m²
B)What is the amplitude of the electric field at the GPS receiver in part = 2.71 x 10 ∧-6nc
C)What is the amplitude of the magnetic field at the GPS receiver in part = 9.03 x 10∧-15T
D)How long does it take the signal to reach the receiver? = 6.73 x 10 ∧-2s
E)If the receiver is a square panel 2.00 on a side that absorbs all of the beam, what average pressure does the signal exert on it = 3.25 x10 ∧-25pa
F)What wavelength must the receiver be tuned to? = 0.190m
Explanation:
check attached files below for explanation
