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SpyIntel [72]
3 years ago
5

The driver of a sports car traveling at 10.0⁣m/s steps down hard on the accelerator for 5.0⁣s and the velocity increases to 30.0

⁣m/s. What was the average acceleration of the car during the 5.0s time interval?
Physics
1 answer:
xxTIMURxx [149]3 years ago
3 0

Answer:

a=4m/s^{2}

Explanation:

From the concept of <u>average acceleration</u> we know that

a=\frac{v_{2}-v_{1} }{t_{2}-t_{1}  }

From the exercise we know that

v_{2}=30m/s\\v_{1}=10m/s\\t_{2}=5s\\t_{1}=0s

So, the average acceleration of the car is:

a=\frac{30m/s-10m/s}{5s}=4m/s^{2}

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m*a = M*a'

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because M > m, then M/m > 1.

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