1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lana66690 [7]
4 years ago
5

Plz help me answer this is my Final Exam!!!

Physics
1 answer:
Ostrovityanka [42]4 years ago
8 0

It's answer number four

You might be interested in
What is the current through resistor #1? (must include unit - A)
Vlad1618 [11]

Answer: 3A

Explanation:

First, we must calculate voltage by summing the reciprocal of the resistances in the circuit

1/40 +1/40 = 2/40 = 1/20 = 1/R, so R = 20Ω

Using Ohm's Law, I = V/R, so the current I is I = 120/20 = 6A

Using Kerchoff's Circuit Law, we know that current will split evenly at a junction, so each resistor will get one half, or 3A.

7 0
3 years ago
The direction in which heat flows between two bodies depend on their
Alchen [17]

Answer:

b. jury wasn't on ayesha akter

6 0
4 years ago
A light beam travels at 1.94×108 in quartz. The wavelength of the light in quartz is 355 .Part AWhat is the index of refraction
Alja [10]

A) 1.55

The speed of light in a medium is given by:

v=\frac{c}{n}

where

c=3\cdot 10^8 m/s is the speed of light in a vacuum

n is the refractive index of the material

In this problem, the speed of light in quartz is

v=1.94\cdot 10^8 m/s

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

n=\frac{c}{v}=\frac{3\cdot 10^8 m/s}{1.94\cdot 10^8 m/s}=1.55

B) 550.3 nm

The relationship between the wavelength of the light in air and in quartz is

\lambda=\frac{\lambda_0}{n}

where

\lambda is the wavelenght in quartz

\lambda_0 is the wavelength in air

n is the refractive index

For the light in this problem, we have

\lambda=355 nm\\n=1.55

Therefore, we can re-arrange the equation to find \lambda_0, the wavelength in air:

\lambda_0 = n\lambda=(1.55)(355 nm)=550.3 nm

4 0
4 years ago
A pendulum has 141 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
Lubov Fominskaja [6]
Assume that energy losses (due to aerodynamic resistance or bearing friction are negligible).

At the highest point, the pendulum has its maximum potential energy (PE) and zero kinetic energy (KE). The total energy is equal to the PE = 141 J.

At the lowest point, the pendulum has its maximum KE, and zero PE. The total energy is equal to the KE.

Because energy is preserved, therefore
KE at the lowest point  = PE at the highest point  = 141 J.

Answer:  141 J
3 0
3 years ago
A 55.0 kg student feels a
natta225 [31]

Explanation:

mass of student(M1)=55

mass of book(M2)=?

distance(d)=0.435m

gravitational constant (G)=6.67×10^-11

force(F)=2.68×10^-8

Now,

F=GM1M2/d^2.

then do the numericals .It's taking long time so I escaped Sorry

5 0
3 years ago
Other questions:
  • You set out to design a car that uses the energy stored in a flywheel consisting of a uniform 80-kg cylinder of radius r that ha
    12·1 answer
  • A student was taking a rock-climbing class that used an indoor climbing wall. before he started, the instructoe asked for his we
    11·1 answer
  • What is the passenger's apparent weight at t=1.0s?
    15·2 answers
  • Why does your body feels like it is being pushed back when the car starts back up again
    6·1 answer
  • Work may be measured using units of <br> A.watts<br> B.newton<br> C.joules<br> D.newtons per second
    10·1 answer
  • How do vibrations cause sound waves
    12·2 answers
  • A book that weighs 16N is on top of a shelf that is 3m high. What is the work required to
    12·1 answer
  • The environment affects people, but people don't affect the environment.<br><br><br>TRUE OR FALSE
    10·1 answer
  • This force involves the attraction between objects with mass. (2 points) i need it asap
    9·1 answer
  • Alright eksqijakojqnlqozjzbw.wlisj
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!