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lana66690 [7]
3 years ago
5

Plz help me answer this is my Final Exam!!!

Physics
1 answer:
Ostrovityanka [42]3 years ago
8 0

It's answer number four

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In an experiment to estimate the acceleration due to gravity, a student drops a ball at a distance of 1 m above the floor. His l
anyanavicka [17]

Answer:

9.45179\ m/s^2

s=4.725895t^2

Explanation:

t = Time taken = 0.46

u = Initial velocity

v = Final velocity

s = Displacement = 1 m

a = Acceleration

s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0\times 0.46+\frac{1}{2}\times a\times 0.46^2\\\Rightarrow a=\frac{1\times 2}{0.46^2}\\\Rightarrow a=9.45179\ m/s^2

The acceleration due to gravity is 9.45179 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow s=\frac{1}{2}at^2\\\Rightarrow s=\dfrac{1}{2}9.45179t^2\\\Rightarrow s=4.725895t^2

The function is s=4.725895t^2

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Jak můžeme videt ze se meni cas
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a jak to chces vidieť nápis podrobnejsie

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Alexandra knows that the atomic number of the element potassium, K, is 19. She also knows that one particular isotope of potassi
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I believe the answer is 58 but I’m not sure
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Explain why liquids solidify when they are cooled.
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Because the molecules that move freely begin to compact closer together, with less heat, means less molecular activity. 
8 0
3 years ago
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The half-wave rectifier circuit of vs(t) = 170 sin(377t) V and a load resistance R = 15Ω. Determine: a. The average load current
irina1246 [14]

Answer:

a  average load current = 11.33 A

b rms load current = 8.02A

c true power =962.64 W

d apparent power =962.64 W

e. power factor cosθ =1

Explanation:

Vs (t) = 170 sin(377t) v

Vm =170v

Vrms = 170/√2 =120.23 v

Im = Vm/R = 170/15 = 11.33 A

Irms = Im/ √2 = 11.33/√2 =8.02A

Resistors are electronic components that consume energy

the power in a resistor is given by  P =IVcosθ ; in a resistor cosθ =1

P =IV

The electrical power consumed by a resistance, (R) is called the true or real power

and is obtained by multiplying the rms voltage with the rms current.

P= Vrms × Irms

120.03×8.02

P= 962.64 W ; true power

apparent power = Vrms × Irms

=120.03×8.02

= 962.64W ; apparent power

power factor cosθ = true power/ apparent power

cosθ = 962.64/962.64

cosθ = 1

For the purely resistive circuit, the power factor is 1 , because the reactive power is equal to zero (0).

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3 years ago
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