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miskamm [114]
3 years ago
13

5.1 ounces to grams.

Chemistry
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer: here’s the answer

Explanation:5.1 ounces =

144.583 grams

Formula:

for an approximate result, multiply the mass value by 28.35

Firdavs [7]3 years ago
5 0

Answer:

144.583 grams

Explanation:

thats what i found

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How many moles of hydrogen atoms are there in 1.25 x 1025 molecules of ethane? (C2H6)
krek1111 [17]

Answer:

124.56 moles of Hydrogen atoms.

Explanation:

We'll begin by calculating the number of moles of ethane that contains 1.25×10²⁵ molecules. This can be obtained as follow:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10²³ molecules. This implies that 1 mole of ethane also contains 6.02x10²³ molecules.

Thus, 6.02x10²³ molecules are present in 1 mole of ethane.

Therefore, 1.25×10²⁵ molecules are present in = 1.25×10²⁵/6.02x10²³ = 20.76

Therefore, 20.76 moles of ethane contains 1.25×10²⁵ molecules.

Finally, we shall determine the number of mole of Hydrogen in 20.76 moles of ethane. This can be obtained as follow:

Ethane has formula as C2H6.

From the formula, 1 mole of ethane, C2H6 contains 6 moles of Hydrogen atoms.

Therefore, 20.76 moles of ethane will contain = 20.76 × 6 = 124.56 moles of Hydrogen atoms.

Therefore, 1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.

7 0
3 years ago
The humidity levels inside the greenhouse.
PtichkaEL [24]

Answer:

Most indoor growers will want to aim for 50-70% relative humidity, although 60-80% is usually tolerable.

Explanation:

7 0
3 years ago
Your lab group forgot to record the initial volume measurement on the buret and assumed later that it started at 0.00 mL when th
kherson [118]

Answer:

Calculated molarity of acid is higher than the actual concentration.

Explanation:

For an acid-base titration, the following equation is obeyed for calculation-

                                   C_{acid}.V_{acid}=C_{base}.V_{base}

where, C represents concentration and V represents volume.

So, C_{acid}=\frac{C_{base}.V_{base}}{V_{acid}}

Here, C_{base} and V_{acid} are constants.

Actual volume of base added from burette is lesser than the volume used (based on assumption) for calculation of concentration of acid.

So, actual value of V_{base} is lesser. Hence calculated concentration or molarity of acid is higher than the actual concentration.

4 0
3 years ago
Which two particles each have a mass approximately equal to one atomic mass
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The number of protons and neutrons are approximately equal to the atomic mass
4 0
3 years ago
The Ksp of mercury(II) hydroxide, Hg(OH)2, is 3.60×10^−26 . Calculate the solubility of this compound in grams per liter.
Stells [14]

The solubility of the compound is obtained as 9.5 * 10^-14 M.

<h3>What is the solubility product?</h3>

The solubility product refers to the equilibrium constant that shows the extent to which a thing is soluble in water, Now we can write the solubility product as;

Ksp = [Hg^2+] [2OH^-]^2

Let  [Hg^2+]  =  [OH^-] = x

Then I can write;

Ksp = x * (2x)^2

Ksp = 4x^3

When x = solubility

x = ∛Ksp/4

Ksp =  3.60×10^−26

x =  ∛ 3.60×10^−26/4

x = 9.5 * 10^-14 M

Learn more about Ksp:brainly.com/question/27132799

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8 0
2 years ago
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