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1 year ago

Gym lockers are to be numbered from 1 through 99 using metal numbers to be nailed onto each locker. how many 7s are needed?

Physics

1 answer:

Georgia [21]1 year ago

3 0

There are nineteen gym lockers that would have the digit "seven" on them.

<h3>How many sevens are there?</h3>

In this problem, we need to know the number of gym lockers that would have the number 7 attached to them either as tens or digit as the lockers are numbered from one to ninety nine.

Let us now proceed which lockers would have the digit "seven" on them;

7, 17, 27, 37, 47, 57, 67, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 87, 97. We can see that there are nineteen gym lockers that would have the digit "seven" on them.

Learn more about digits:brainly.com/question/28458348

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The student applies a net force of 4.5 N to the 1.5 kg textbook.

Kitty [74]

Answer:

3 m/s²

Explanation:

acceleration = Force / mass; 4.5/1.5 = 3

4 0

3 years ago

Three resistors having resistances of LaTeX: 4.0\;\Omega4.0 Ω, LaTeX: 6.0\;\Omega6.0 Ω, and LaTeX: 10.0\;\Omega10.0 Ω are connec

aalyn [17]

Answer:

Explanation:

Given that three resistor of resistance

R1 = 4 Ω

R2 = 6 Ω

R3 = 10 Ω

The resistor are connected in parallel, the equivalent resistance is

1 / Req = 1 / R1 + 1 / R2 + 1 / R3

Rearranging this we have

Req = R1•R2•R3 / (R2•R3 + R1•R3 + R1•R2)

Req = 4 × 6 × 10 / (6×10 + 4 × 10 + 4 × 6)

Req = 240 / (60 + 40 + 24)

Req = 240 / 124

Req = 1.94 Ω

The parallel connection is connected in series with a battery and a resistor.

Resistor resistance is

r = 2 Ω

Supply voltage of the battery is 12V

V = 12V

Let find the current flowing in the circuit.

V = I(Req + r)

I = V / (Req + r)

I = 12 / (1.94 + 2)

I = 12 / 3.94

I = 3.05A

So, this is the current flowing in the circuit and It is the same current that will be shared by the parallel resistance.

We can calculated the voltage across the parallel resistance

From ohms las

V = iR

V = I × Req

V = 3.05 × 1.94

V = 5.92 V.

Then, this the voltage across each parallel resistor.

Then, to know the current in the 10ohms resistance

V = iR

I = V / R3.

I = 5.92 / 10

I = 0.592 A.

The current in the 10 ohms resistor is 0.59A

5 0

3 years ago

If a proton and an electron are released when they are 6.50×10⁻¹⁰ m apart (typical atomic distances), find the initial accelerat

Cerrena [4.2K]

Answer:

(a) Acceleration of electron= 5.993×10²⁰ m/s²

(b) Acceleration of proton= 3.264×10¹⁷ m/s²

Explanation:

Given Data

distance r= 6.50×10⁻¹⁰ m

Mass of electron Me=9.109×10⁻³¹ kg

Mass of proton Mp=1.673×10⁻²⁷ kg

Charge of electron qe= -e = -1.602×10⁻¹⁹C

Charge of electron qp= e = 1.602×10⁻¹⁹C

To find

(a) Acceleration of electron

(b) Acceleration of proton

Solution

Since the charges are opposite the Coulomb Force is attractive

$F=\frac{1}{4(\pi)Eo }\frac{|qp*qe|}{r^{2} }\\ F=(8.988*10^{9}Nm^{2}/C^{2})*\frac{(1.602*10^{-19})^{2} }{(6.50*10^{-10} )^{2} } \\F=5.46*10^{-10}N$

From Newtons Second Law of motion

F=ma

a=F/m

For (a) Acceleration of electron

$a=F/Me\\a=(5.46*10^{-10} )/9.109*10^{-31}\\ a=5.993*10^{20}m/s^{2}$

For(b) Acceleration of proton

$a=F/Mp\\a=(5.46*10^{-10} )/1.673*10^{-27} \\a=3.264*10^{17}m/s^{2}$

3 0

3 years ago

Why is external fertilization not possible in organisms that live on land

Softa [21]

because the sperm and the egg will dry out

4 0

4 years ago

If a wave had a wave speed of 1000 m/s and a frequency of 500 Hz, what is its wavelength?

Reil [10]

Answer:

<h2>2 meters</h2>

Explanation:

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7 0

3 years ago