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saw5 [17]
2 years ago
8

Explain the following observations:

Physics
1 answer:
Deffense [45]2 years ago
6 0

Answer and Explanation:

a. An oxygen-filled balloon is not able to float in the air, because the oxygen inside the balloon is of the same density, that is, the same "weight" as the oxygen outside the balloon and present in the atmosphere. The balloon can only float if the gas inside it is less dense than atmospheric oxygen. Helium gas is less dense than atmospheric gas, so if a balloon is filled with helium gas, that balloon will be able to float because of the difference in density.

b. The ship is able to float in the water because its steel construction is hollow and full of air. This makes the average density of this ship less than the density of water, which makes the ship lighter than water and for this reason, this ship is able to float. In addition, the ship is partially immersed, allowing the weight of the ship on the water to counteract the buoyant force that the water promotes on the ship. Weight and buoyant are two opposing forces that keep the ship afloat.

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If 4 x 10^21 electrons pass through a wire connected to a 15 ohm resistor in 3 s, how much electric
sammy [17]

Answer:

1.) Current = 213.33A

2.) Potential difference = 3200 V

Explanation:

Given that

Number of electrons n = 4 x 10^21 electrons

Resistance R = 15 ohm

Time t = 3 s

From the definition of current ;

Current is the rate of flow of changes. That is,

Current I = Q/t

Where

Q = 4 × 10^21 × 1.6 × 10^-19

Q = 460C

Current I = 460/3

Current I = 213.33 A

Using Ohms law which state that

V = IR

Substitute the resistance R and current I into the formula above

Potential difference V = 213.3 × 15

Potential difference V = 3200 V

6 0
3 years ago
Ford used to make a 7.0 liter engine. Calculate how many many cubic inches would be the same size engine.
Anestetic [448]

Answer : The volume of engine in cubic inches is, 427.166\text{ inch}^3

Explanation :

As we are given that the volume of engine is, 7.0 liters. Now we have to calculate the volume of engine in cubic inches.

Conversion used :

1\text{ liter}=1000cm^3

So, 7\text{ liter}=7000cm^3

1\text{ inch}=2.54cm

or,

1cm=\frac{1}{2.54}\text{ inch}

1cm^3=(\frac{1}{2.54}\text{ inch})^3

As,

1cm^3=(\frac{1}{2.54}\text{ inch})^3

So,

7000cm^3=\frac{7000cm^3}{1cm^3}\times (\frac{1}{2.54}\text{ inch})^3=427.166\text{ inch}^3

Thu, the volume of engine in cubic inches is, 427.166\text{ inch}^3

3 0
3 years ago
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