Answer: the amphoteric line, mental- nonmetal line, metalloid line, staircase, semimetal line. it can be called any of these names
Answer:
a) No difference
Explanation:
Since the billiard balls are identical , they have the same mass. Also they have the same speed
Since the angular momentum is conserved and the total energy is conserved ( if we assume elastic collision)
1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²
where m= mass , vi= initial velocity , vf= final velocity
since m1=m2=m , vi1=vi2=vi
1/2 m1 * v i1² +1/2 m2 * v i1² = 1/2 m1 * v f1² +1/2 m2 * v f2²
m * v i² = 1/2 m (v f1² +v f2² )
vi² = 1/2(v f1² +v f2² )
since the 2 balls are indistinguishable from each other (they have identical initial mass and velocity) there is no reason for a preferential speed for one of the balls and therefore its velocities must be equal . Thus vf1=vf2=vf
therefore
v i² = 1/2(v f1² +v f2² ) = v i1² = 1/2* 2vf² = vf²
and thus
vi= vf
in conclusion, there is no difference in speed after the rebound
I think it is false, because why would is be stronger in a different state?
4.266 m is the radius of the circular path the electron follows.
Given
Speed of electron (v) = 7.5 × 10⁶ m/s
Earth's Magnetic Field (B) = 1 × 10⁻⁵ T
We already know that
Mass of electron (m) = 9.1 × 10⁻³¹ kg
Charge on electron (q) = 1.6 × 10⁻¹⁹ C
According to the formula
Radius of circular path(r) = mass on electron × speed/ Charge × Magnetic field
Radius of circular path(r) = m × v/q × B
Put the values into the formula
r = 9.1 × 10⁻³¹ × 7.5 × 10⁶/ 1.6 × 10⁻¹⁹ × 10⁻⁵
On solving, we get
r = 4.266 m
Hence, 4.266 m is the radius of the circular path the electron follows.
Learn more about magnetic field here brainly.com/question/26257705
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