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hammer [34]
2 years ago
14

How much net force is needed to accelerate a 15 kg mass at 2.8 m/s^2

Physics
1 answer:
Lera25 [3.4K]2 years ago
4 0
Refer to the 2th Law of Newton

F = m. a

F = 15 x 2.8 = 42 N
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Acceleration is a change in speed or direction over time. In what two ways does the sled accelerate as it descends?
Anna007 [38]

Answer:

By force and sloppy surface.

Explanation:

By applying force on the sled and slope of the path are the two ways the sled accelerate as it descends. If there is more friction between sled and the ground then force is required to push the sled to move downward while on the other hand, if the path on which sled moves is sloppy then it will move automatically without the use of force, so these two ways can accelerate the sled.

4 0
2 years ago
A student is studying the potential energy change of a 50 kg object raised 110 km above Earth's surface. What will be the percen
Law Incorporation [45]

Answer:

The percentage error is given by 99.9 %

Explanation:

Given:

Mass of object m = 50 kg

Height h = 110 km

From the formula of potential energy,

   U = mgh

Where g = 9.8 \frac{m}{s}

   U = 50\times 9.8 \times 110000

Here true value of potential energy,

   U = 50 \times 9.8 \times 11 \times 10^{4}

Approximate value of student,

   U = 50 \times 9.8 \times 110

Absolute error is given by

    = true value - approximate value

    = 50 \times 9.8 \times 11 \times 10^{4} - 50 \times 9.8 \times 110

    = 53846100

Hence percentage error,

    = \frac{53846100}{50 \times 9.8 \times 11 \times 10^{4} }

    = 0.999 \times 100 %

    = 99.9 %

Therefore, the percentage error is given by 99.9 %

7 0
3 years ago
A force does work on an object if a component of the force is
IrinaK [193]

Answer:

A force does work on an object if a component of the force is parallel to the displacement of the object.

Explanation:

Work, a measurement of energy is said to be done when a force applied to an object results in the movement of that object to a certain distance and direction. Force is the act of push or pulls occurs on an object as a result of the interaction between that object with another one and displacement is the distance and direction covered by that object as a result of the force applied on it.

The work done (W) by a constant force (F) is equal to the product of the force in the direction of displacement of the object and the distance (d) moved by the object i.e., W = F * d.

The angle between the displacement and the force is θ, then the work done, W = Fd cos θ  ........ (1)

Positive work - Force acts in the same direction with respect to the displacement of the object. Here, θ is zero, so cos θ i.e., cos 0 is 1. Therefore, from the equation (1), W = Fd (i.e., work done by the force is positive).

Negative work - Force acts in the opposite direction with respect to the displacement of the object.  Here, θ is 180°, so cos θ i.e., cos 180° is -1. Therefore, from the equation (1), W = -Fd (i.e., work done by the force is negative).

If a force is applied to an object and it does not move, then the work done is zero i.e., W = F * 0 = 0. Also, if the force and displacement are at right angle to each other, then θ is 90°. Therefore, from the equation (1), W = 0 since cos 90° is zero.

7 0
3 years ago
What is the atomic number of an atom?
Sever21 [200]

Answer:

B, the number of protons.

Explanation:

It is the number of protons found in the nucleus of the atom.

4 0
2 years ago
How many outer-orbital electrons are found in an atom of:a) Na?b) P?c) Br?d) I?e) Te?f) Sr?
lys-0071 [83]

Answer:

  1. Na=1
  2. P=5
  3. Br=7
  4. I=7
  5. Te=6
  6. Sr=2

6 0
1 year ago
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