Answer:

Explanation:
As we know that the orbital speed is given as

here we know that
v = 5500 m/s


now we have


now acceleration due to gravity of planet is given as



now range of the projectile on the surface of planet is given as



A) 4.7 cm
The formula for the angular spread of the nth-maximum from the central bright fringe for a diffraction from two slits is

where
n is the order of the maximum
is the wavelength
is the distance between the slits
In this problem,
n = 5


So we find

And given the distance of the screen from the slits,

The distance of the 5th bright fringe from the central bright fringe will be given by

B) 8.1 cm
The formula to find the nth-minimum (dark fringe) in a diffraction pattern from double slit is a bit differente from the previous one:

To find the angle corresponding to the 8th dark fringe, we substitute n=8:

And the distance of the 8th dark fringe from the central bright fringe will be given by

Answer:
This is false
Explanation:
This is why the answer to this question is false. If these types of objects (2 points connected) should pass through same sets of 3 points, irrespective of the order that each object was plotted, we will not get identical shapes created.
The shape that is going to be created will be dependent on the pattern/order that was involved in the plotting. If it was identical, then we will have identical shapes. But if the order during plotting is different then we will have different shapes created.
Thank you!
This is related to the energy carried by photons of light the energy of each photon is proportional to the frequency of the light since red light has a lower frequency then violet light and photons of red light carry less energy than the photons of violet light as a result the red protons eject electrons that have less energy than the ejected electrons by Violet photons
Answer and Explanation:
Data provided in the question
Force = 50N
Length = 5mm
diameter = 2.0m = 
Extended by = 0.25mm = 
Based on the above information, the calculation is as follows
a. The Stress of the wire is

here area of circle = perpendicular to the are i.e cross-sectional i.e
= 
= 
Now place these above values to the above formula

= 15.92 MPa
As 1Pa = 1 by N m^2
So,
MPa = 10^6 N m^2
b. Now the strain of the wire is

= 