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hammer [34]
3 years ago
14

How much net force is needed to accelerate a 15 kg mass at 2.8 m/s^2

Physics
1 answer:
Lera25 [3.4K]3 years ago
4 0
Refer to the 2th Law of Newton

F = m. a

F = 15 x 2.8 = 42 N
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how much voltage is in the primary coil if there are 3200 winding in the secondary coil 500 winding in the primary and 25v in th
Tema [17]

Answer:

Voltage in the primary winding of the coil is 3.9 V

Explanation:

As we know by the principle of transformer we have

\frac{V_s}{V_p} = \frac{N_s}{N_p}

here we know that

V_s = 25 volts

N_s = 3200

N_p = 500

now we have

\frac{25}{V_p} = \frac{3200}{500}

V_p = 3.9 Volts

7 0
3 years ago
What is empirical evidence and what's is it not
ladessa [460]
Empirical evidence is information acquired by observation or experimentation. This data is recorded and analyzed by scientists and is a central process as part of the scientific method.
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3 years ago
In one of the classic nuclear physics experiments at the beginning of the 20th century, an alpha particle was accelerated toward
BaLLatris [955]

Answer:

= 4.3 × 10 ⁻¹⁴ m

Explanation:

The alpha particle will be deflected when its kinetic energy is equal to the potential energy

Charge of the alpha particle q₁= 2 × 1.6 × 10⁻¹⁹ C = 3.2 × 10⁻¹⁹ C

Charge of the gold nucleus q₂= 79 × 1.6 × 10⁻¹⁹ = 1.264 × 10⁻¹⁷C

Kinetic energy of  the alpha particle = 5.28 × 10⁶ × 1.602 × 10⁻¹⁹ J ( 1 eV)

=  8.459 × 10⁻¹³

k electrostatic force constant = 9 × 10⁹ N.m²/c²

Kinetic energy = potential energy =   k q₁q₂ / r where r is the closest distance the alpha particle got to the gold nucleus

r = (  9 × 10⁹ N.m²/c² × 3.2 × 10⁻¹⁹ C × 1.264 × 10⁻¹⁷C) / 8.459 × 10⁻¹³

= 4.3 × 10 ⁻¹⁴ m

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develop a plan to test the hardness of a sample of feldspar using the following items glass plate copper penny and streak plate
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Stroke then 3883 you choke <3333333333
6 0
3 years ago
Distance versus Displacement Worksheet
Umnica [9.8K]

when we find the distance we will add all the blocks so

distance = 6+6+4

distance = 14blocks

when we find the displacement we will add and minus too

As you can read he goes to the south 6 and to north 6 so he leave that place and back to the place again so the displacement is 0. and again he goes to the west 4 blocks so the displacement = <em><u>4blocks</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>west</u></em>

6 0
4 years ago
Read 2 more answers
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