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notka56 [123]
3 years ago
6

Carbon-12 and carbon-13 are isotopes of carbon. Which of the following statements is correct?

Chemistry
2 answers:
sashaice [31]3 years ago
7 0

The correct answer on edgenuit.y is

<h2><u>D) They both have the same atomic number.</u></h2>

I hope this helps (:

kiruha [24]3 years ago
3 0
Carbon-13 has 7 neutrons and carbon-12 has 6 neutrons. Carbon-12 is the most common isotope of carbon. Carbon-14 is radioactive and very rare. The symbols for the isotopes of carbon atoms shown here indicate they each have six protons but mass numbers of 14, 13 and 12.
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Dorothy left a frozen juice pop out on the counter. When she returned, the juice pop had melted into a liquid. Which of the foll
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Answer:

B) The molecules were closer together when the juice pop was frozen.

8 0
2 years ago
How many mm are equal to 21 L. How many mg are equal to 9 g. How many grams are equal to 400 kg
liberstina [14]
<span>How many mm are equal to 21 L? 

1 L = </span>1000000 mm

Convert:-

1000000 × 21 = <span>21000000

21 l = </span><span>21000000 mm

</span><span>How many mg are equal to 9 g?

1 g = 1000 mg

Convert:-

9 </span>× 1000 = 9000

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8 0
3 years ago
Need Help ASAP
bagirrra123 [75]

a. pH=2.07

b. pH=3

c. pH=8

<h3>Further explanation</h3>

pH=-log [H⁺]

a) 0.1 M HF Ka = 7.2 x 10⁻⁴

HF= weak acid

\tt [H^+]=\sqrt{Ka.M}\\\\(H^+]=\sqrt{7.2.10^{-4}\times 0.1}\\\\(H^+]=8.5\times 10^{-3}\\\\pH=3-log~8.5=2.07

b) 1 x 10⁻³ M HNO₃

HNO₃ = strong acid

\tt pH=-log[1\times 10^{-3}]=3

c) 1 x 10⁻⁸ M HCl

\tt pH=-log[1\times 10^{-8}]=8

5 0
2 years ago
Graciella divided her grapes equally among 6 friends. If each friend received 16 grapes how many grapes did Graciella have?
DIA [1.3K]

Answer: She had 96 grapes.

Explanation:

3 0
2 years ago
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What transition energy corresponds to an absorption line at 527 nm?​
Ede4ka [16]

Answer:

E = 3.77×10⁻¹⁹ J

Explanation:

Given data:

Wavelength of absorption line = 527 nm (527×10⁻⁹m)

Energy of absorption line = ?

Solution:

Formula:

E = hc/λ

h = planck's constant = 6.63×10⁻³⁴ Js

c = speed of wave = 3×10⁸ m/s

by putting values,

E = 6.63×10⁻³⁴ Js ×  3×10⁸ m/s / 527×10⁻⁹m

E = 19.89×10⁻²⁶ Jm /527×10⁻⁹m

E = 0.0377×10⁻¹⁷ J

E = 3.77×10⁻¹⁹ J

4 0
2 years ago
Read 2 more answers
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