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elena55 [62]
3 years ago
9

7. (04wP2-5)Elements with atomic number 21 to 30 are d-block elements.

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
3 0

Answer :

  • (a) zn

Explanation:

  • (b) a ligand is an ion or molecule that binds to the central metal atom to form a cordinate complex.
  • (c)
<h3> above</h3>

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6/5/8/9

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What happens to the energy of the universe during a chemical or physical process
yulyashka [42]

Answer:

unchanged

Explanation:

In any chemical of physical process, energy is neither created nor destroyed. A process that absorbs the heat from the surroundings. ... What happens to the energy of the universe during a chemical or physical process? During any chemical or physical process, the energy of the universe remains unchanged.

5 0
3 years ago
5. What is the number value of absolute zero? *<br> (
Norma-Jean [14]

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0

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it is 0 I believe nothing

7 0
2 years ago
The student recorded the mass of the cup + sample incorrectly and started with 2.20 g of hydrated compound but used 2.00 g in th
gtnhenbr [62]

Answer:

low

Explanation:

We were informed in the question that the student had incorrectly recorded the mass of cup + sample as 2.20 g but inadvertently used 2.00 g in the calculations.

This error will cause a slight decrease in the mass of water and ultimately decrease the number of moles of water in the hydrate.

What i am saying is that the number of moles of water obtained in the calculation will be artificially low.

4 0
2 years ago
Water (10 kg/s) at 1 bar pressure and 50 C is pumped isothermally to 10 bar. What is the pump work? (Use the steam tables.) O -7
11Alexandr11 [23.1K]

Explanation:

For an isothermal process equation will be as follows.

                W = nRT ln\frac{P_{1}}{P_{2}}

It is given that mass is 10 kg/s or 10,000 g/s (as 1 kg = 1000 g). So, calculate number of moles of water as follows.

                    No. of moles = \frac{mass}{\text{molar mass}}

                                           = \frac{10000 g/s}{18 g/mol}

                                           = 555.55 mol/s

                                           = 556 mol/s (approx)

As T = 50^{o}C or (50 + 273.15) K = 323.15 K. Hence, putting the given values into the above formula as follows.

                  W = nRT ln[/tex]\frac{P_{1}}{P_{2}}[/tex]

                      = 556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times ln\frac{1}{10}    

                     = 556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times -2.303    

                     = -3440193.809 J/s

Negative sign shows work is done by the pump. Since, 1 J = 0.001 kJ. Therefore, converting the calculated value into kJ as follows.

                     3440193.809 J/s \times \frac{0.001 kJ}{1 J}

                          = 3440.193 kJ/s

                          = 3451 kJ/s (approx)

Thus, we can conclude that the pump work is 3451 kJ/s.

6 0
3 years ago
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