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SpyIntel [72]
3 years ago
5

Write the electron configuration when Sodium loses one electron

Chemistry
2 answers:
Maksim231197 [3]3 years ago
3 0

Answer:

2, 8

Explanation:

Sodium Na has 11 electrons.

The electronic configuration of sodium is 2, 8, 1

Sodium loses 1 electron, the new atom has 10 electrons.

11 - 1 = 10

2, 8

lara [203]3 years ago
3 0

Answer:

Sodium cation loses one electron, so Na+: 1s(2)2s2(2)p(6)3s(1) = Na+: 1s(2)2s(2)2p(6). P: 1s(2)2s(2)2p(6)3s(2)3p(3)

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Which element has higher ionization energy? chlorine or carbon
PtichkaEL [24]

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chlorine has higher ionization than carbon

Explanation:

Chlorine is only one row below carbon, but it is three columns to the right in this case the IP of chlorine would be predicted to be greater than the IP of carbon.

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What happens on a molecular level when a diatomic molecule is a gas but is then cooled to a solid?
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Explanation:

Hopefully that helps!

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3 years ago
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3 0
2 years ago
Read 2 more answers
(c) Assume you have an equilibrium mixture of [A], [B], and [C] at 298K and that the
djyliett [7]

Answer:

Explanation:

1. The amount of CaCO3 must be so small that  

P

CO

2

 is less than KP when the CaCO3 has completely decomposed. In other words, the starting amount of CaCO3 cannot completely generate the full  

P

CO

2

 required for equilibrium.

3. The change in enthalpy may be used. If the reaction is exothermic, the heat produced can be thought of as a product. If the reaction is endothermic the heat added can be thought of as a reactant. Additional heat would shift an exothermic reaction back to the reactants but would shift an endothermic reaction to the products. Cooling an exothermic reaction causes the reaction to shift toward the product side; cooling an endothermic reaction would cause it to shift to the reactants’ side.

5. No, it is not at equilibrium. Because the system is not confined, products continuously escape from the region of the flame; reactants are also added continuously from the burner and surrounding atmosphere.

7. Add N2; add H2; decrease the container volume; heat the mixture.

9. (a) ΔT increase = shift right, ΔP increase = shift left; (b) ΔT increase = shift right, ΔP increase = no effect; (c) ΔT increase = shift left, ΔP increase = shift left; (d) ΔT increase = shift left, ΔP increase = shift right.

11. (a)  

K

c

=

[

CH

3

OH

]

[

H

2

]

2

[

CO

]

; (b) [H2] increases, [CO] decreases, [CH3OH] increases; (c), [H2] increases, [CO] decreases, [CH3OH] decreases; (d), [H2] increases, [CO] increases, [CH3OH] increases; (e), [H2] increases, [CO] increases, [CH3OH] decreases; (f), no changes.

13. (a)  

K

c

=

[

CO

]

[

H

2

]

[

H

2

O

]

; (b) [H2O] no change, [CO] no change, [H2] no change; (c) [H2O] decreases, [CO] decreases, [H2] decreases; (d) [H2O] increases, [CO] increases, [H2] decreases; (f) [H2O] decreases, [CO] increases, [H2] increases. In (b), (c), (d), and (e), the mass of carbon will change, but its concentration (activity) will not change.

15. Only (b)

17. Add NaCl or some other salt that produces Cl− to the solution. Cooling the solution forces the equilibrium to the right, precipitating more AgCl(s).

19. (a)

Hope this helps :)

3 0
3 years ago
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