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salantis [7]
3 years ago
9

Find the values of y = p(x) = √x for x = 0, 1.44, 2.25, 3.24, 4.41, 5.29 Then plot the corresponding points on a grap

Mathematics
1 answer:
ryzh [129]3 years ago
5 0
Below is the calculation showing the values of y or p(x) in each value of x.
                                  y = p(x) = √x
                                       y = √0 = 0
                                       y = √1.44 = 1.2
                                       y = √2.25 = 1.5
                                       y = √3.24 = 1.8
                                       y = √4.41 = 2.1
                                       y = √5.29 = 2.3
Therefore, the ordered pairs in the graph are (0,0), (1.44, 1.2), (2.25,1.5),(3.24,1.8), (4.41,2.1), and (5.29,2.3). 

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Answer:

10.08+4.99x\leq 50

x\leq 8

The maximum pounds of cheese that Ariana can buy is 8

Step-by-step explanation:

Let

x ---> the amount of cheese In pounds, that  Ariana can buy

we know that

The cost of 3 loaves of bread plus the cost of the cheese must be less than or equal to $50

so

The inequality that represent this situation is

3(3.36)+4.99x\leq 50

10.08+4.99x\leq 50

solve for x

subtract 10.08 both sides

4.99x\leq 50-10.08

4.99x\leq 39.92

divide by 4.99 both sides

x\leq 8

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3 0
3 years ago
Let’s pretend that we want to give our employees in total a28% raise in the next two years, but we want to spread out aconsisten
Roman55 [17]

Solution

- The solution steps are given below:

\begin{gathered} \text{ Let the original amount be X} \\  \\ \text{ If we want a 28\% raise over the next two years, then it means that the amount will be:} \\ X+\frac{28}{100}X=1.28X \\  \\ \text{ If we want to give them a consistent raise each year, we can compute the scenario as follows:} \\ \text{ Let the percentage be }y \\  \\ X+y\%\text{ of }X=\text{ Salary after first year} \\  \\ (X+y\%\text{ of }X)+y\%\text{ of }(X+y\%\text{ of }X)\text{ = Salary after second year.} \\  \\ \text{ But we already know that the salary after second year is }1.28X \\ \text{ Thus, we can say:} \\ (X+y\%\text{ of }X)+y\%\text{ of }(X+y\%\text{ of }X)=1.28X \\  \\ \text{ Simplifying, we have:} \\ X+\frac{yX}{100}+\frac{y}{100}(X+\frac{yX}{100})=1.28X \\  \\ \text{ Divide through by }X \\ 1+\frac{y}{100}+\frac{y}{100}(1+\frac{y}{100})=1.28 \\  \\ \text{ Subtract 1 from both sides and expand the brackets} \\ \frac{y}{100}+\frac{y}{100}+(\frac{y}{100})^2=1.28-1=0.28 \\  \\ \frac{2y}{100}+(\frac{y}{100})^2=0.28 \\  \\ \text{ Multiply both sides by }100^2 \\ 200y+y^2=2800 \\  \\ \text{ Rewrite, we have:} \\ y^2+200y-2800=0 \\  \\ Solving\text{ the equation using the Quadratic formula, we have that:} \\ y=\frac{-200\pm\sqrt{200^2-4(-2800)}(1)}{2(1)} \\  \\ y=-213.137\text{   or   }13.137 \\  \\ \text{ Since the change in salary is an increase, thus, the rate }y\text{ has to be positive.} \\ \text{ Thus, } \\ y=13.137\approx13.14\% \\  \\  \end{gathered}

Final Answer

y = 13.14%

The screenshots of the solution are:

5 0
1 year ago
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Contact [7]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
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