2 years ago

What is being despited in this picture

Physics

1 answer:

yan [13]2 years ago

8 0

Answer:

i am guessing for reflection but not so sure

You might be interested in

Which of the following occurs with both a cold front and a mountain breeze?

BigorU [14]

Answer:

b warm air rises

Explanation:

5 0

2 years ago

Match the organs to the functions they perform during digestion.<br> passes food to esophagus

mixas84 [53]

Answer:

the mouth I think

Because: the oesophagus is the throat and the mouth is how the food gets to the oesophagus. might be wrong because I'm not sure about the organ part but I'm pretty sure that's all it could be

8 0

2 years ago

Evaluate u+xy where U=3 X=4 Y=7

Reptile [31]

Answer:

Explanation:

Given:

U=3

X=4

Y=7

u + xy

Substitute the given values to the equation:

3 + (4)(7)

3 + 28

6 0

2 years ago

The D.A.R.E. program (“Drug Abuse Resistance Education”) began in 1983. In this program, police officers taught special 45-minut

melisa1 [442]

Answer:

the correct answer is practicing refusal strategies can help students stay sober

Explanation:

7 0

2 years ago

A diffraction grating with 600 lines/mmlines/mm is illuminated with light of wavelength 510 nmnm. A very wide viewing screen is

Ksenya-84 [330]

Answer:

A.2.95 m

B.7

Explanation:

We are given that

Diffraction grating=600 lines/mm

d= $\frac{1 mm}{600}=\frac{1\times 10^{-3} m}{600}=1.67\times 10^{-6} m$

Wavelength of light, $\lambda=510 nm=510\times 10^{-9} m$

l=4.6 m

A.We have to find the distance between the two m=1 bright fringes

$sin\theta=\frac{m\lambda}{d}$

For first bright fringe, =1

$sin\theta=\frac{1\times 510\times 10^{-9}}{1.67\times 10^{-6}}=0.305$

$\theta=sin^{-1}(0.305)=17.76^{\circ}$

The distance between two m=1 fringes

$x=2ltan\theta=2\times 4.6 tan(17.76^{\circ})=2.95 m$

Hence, the distance between two m=1 fringes=2.95 m

B.For maximum number of fringes,

$sin\theta=1$

$sin\theta=\frac{m\lambda}{d}$

Substitute the values

$1=\frac{m\times 510\times 10^{-9}}{1.67\times 10^{-6}}$

$m=\frac{1.67\times 10^{-6}}{510\times 10^{-9}}=3.3\approx 3$

Maximum number of bright fringes on the scree= $2m+1=2(3)+1=7$

8 0

2 years ago