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MAXImum [283]
3 years ago
14

Draw a distance over time graph of a dog that is tied to a 4 foot rope and travels in 1 complete circle

Physics
1 answer:
Soloha48 [4]3 years ago
6 0
I think this is the answer. I hope you can understand.

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Which is not an example of a force?
NNADVOKAT [17]

Answer:

possibly A?

Explanation:

just feels right man

7 0
3 years ago
Many pigeons live near Martyn’s air conditioning vents. Martyn isn’t able to clean the vents properly, and they often contain dr
Furkat [3]

Answer:

B) Aerosol

The particles from the pigeon droppings are likely to be transmitted from the air vents directly into Martyn's respiratory system

3 0
3 years ago
Please help!!!!!! please help!!!!!! please help!!!!!!​
natulia [17]

Answer:

The answer is: wavelength

Explain:

Or crest

3 0
2 years ago
A velocity selector has a magnetic field of magnitude 0.22 T perpendicular to an electric field of magnitude 0.51 MV/m.
ohaa [14]

Answer:

speed of a particle  = 2.31 × 10^{6} m/s

energy of proton required = 27.77 KeV

energy of electron required =  15.171 eV

Explanation:

given data

magnetic field of magnitude = 0.22 T

electric field of magnitude = 0.51 MV/m

to find out

speed of a particle and energy must protons have to pass through undeflected and  energy must electrons have to pass through undeflected

solution

we know that force due to magnetic and electric field is express as

force due to magnetic field B = qvB    ..............1

and force due to electric field E = qE   .....................2

so without deflection force due to magnetic field  = force due to electric field  

so here qvB = qE

and V = \frac{E}{B}    ...................3

put here value

V =  \frac{0.51*10^6}{0.22}

speed of a particle  = 2.31 × 10^{6} m/s

and

now energy of proton required will be here as

energy of proton required = mass of proton × \frac{V^2}{2}

put here value

energy of proton required = 1.67 × 10^{-27} × \frac{(2.31*10^6)^2}{2}

energy of proton required = 4.45 × 10^{-15} J

energy of proton required = 4.45 × 10^{-15} J ÷ (1.602 × 10^{-19}

energy of proton required = 27777.777 eV

energy of proton required = 27.77 KeV

and

now we get here energy of electron required that is

energy of electron required = mass of electron × \frac{V^2}{2}

put here value

energy of electron required = 9.11 × 10^{-31} × \frac{(2.31*10^6)^2}{2}

energy of electron required =  24.305× 10^{-19} J

energy of electron required =  24.305 × 10^{-19} J ÷ (1.602 × 10^{-19}  

energy of electron required =  15.171 eV

5 0
3 years ago
Read 2 more answers
A 68 kg runner exerts a force of 59 N. what is the acceleration of the runner
LuckyWell [14K]
<span>.87 m/s^2 ,hope this helps!!!!!!</span>
8 0
3 years ago
Read 2 more answers
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