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lukranit [14]
4 years ago
11

Javier wants to improve his flexibility and increase his personal discipline. Which community resource should he select?

Physics
1 answer:
Dovator [93]4 years ago
7 0
Karate class, kicking high and ducking fast makes you much more flexible and you must pay respects to those ou fight with and be intune with yourself to do it right, in other words karate is the answer.
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A 67 kg astronaut floating in space throws a 4.2 kg rock at 5.6 m/sec. How fast does the astronaut move backward?
stiks02 [169]
Law of conservation of momentum
67*x=4.2*5.6
5 0
3 years ago
How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius
mixas84 [53]

The magnitude of static friction is

<em>f</em> = <em>mv</em> ²/<em>r</em>

(i.e. the net force acting on the car parallel to the road points toward the center of the curve)

while the net vertical force must be

∑ <em>F</em> = <em>n</em> - <em>mg</em> = 0

because the car is otherwise in equilibrium. Then

==>   <em>n</em> = <em>mg</em>

==>   <em>f</em> = <em>µn</em> = <em>µmg</em> = <em>mv</em> ²/<em>r</em>

==>   <em>µ</em> = <em>v</em> ²/(<em>rg</em>)

We have

<em>v</em> = 101 km/h ≈ 28.1 m/s

<em>r</em> = 110 m

<em>g</em> = 9.80 m/s²

so that

<em>µ</em> = (28.1 m/s)² / ((110 m) <em>g</em>) ≈ 0.730

6 0
3 years ago
Compute the longitudinal strength of an aligned carbon fiber-epoxy matrix composite having a 0.25 volume fraction of fibers, ass
zmey [24]

Answer:

632.5 MPa

Explanation:

\sigma_{m} = Matrix stress at fiber failure = 10 MPa

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The longitudinal strength of a composite is given by

\sigma_{cl}=\sigma_{m}(1-V_f)+\sigma_fV_f\\\Rightarrow \sigma_{cl}=10(1-0.25)+(2.5\times 10^3)\times 0.25\\\Rightarrow \sigma_{cl}=632.5\ MPa

The longitudinal strength of the aligned carbon fiber-epoxy matrix composite is 632.5 MPa

8 0
3 years ago
Pls I need it fast , its for my homework and I can’t find it
frez [133]

Answer:

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Explanation:

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xenn [34]
Body Fossils and Trace Fossils.


Hope I helped and good luck with school. Bye!
3 0
4 years ago
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