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nlexa [21]
3 years ago
7

Which of the following does not serve as a way to neutralize the charge in a body?

Chemistry
2 answers:
Gwar [14]3 years ago
4 0

Answer:

B

Explanation:

xenn [34]3 years ago
3 0

<u>Answer: </u><em>B. Adding more protons to a positively charged body until the number of protons matches the number of electrons</em>

Option B is the appropriate response  

<u>Explanation:</u>

Utilising the equivalent number of inverse charges will kill a charged body.  

Adding more protons to a decidedly charged body until the number of protons coordinates the quantity of electrons won't kill the body since protons are emphatically charged particles. Adding more protons to an emphatically charged body would make it all the more decidedly charged.  

Enabling free electrons to escape from a contrarily charged body will kill since the more negative body leaves the negative electrons.

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Eddi Din [679]

Answer:

C 1:1

Explanation:

Hydrogen loses an electron to becone +1 which is a cation and flourine gains that electron to have a full outer shell on the 2p subshell to become -1 and is an anion so the ratio is 1:1.

4 0
2 years ago
In the "Design a Thermos" lab, the temperature of the thermos was compared with a container that was not insulated.
Hitman42 [59]

Answer:

B

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8 0
3 years ago
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Answer:

64

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2 years ago
Determine whether you can swim in 1.00 x 10^27 molecules of water.​
zloy xaker [14]

Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, N_A, gives the number of molecules in one mole of a substance

N_A ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ N_A

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

7 0
2 years ago
Tell me why in Louisiana it always gotta freaking have a hurricane
Gala2k [10]
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