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nlexa [21]
3 years ago
7

Which of the following does not serve as a way to neutralize the charge in a body?

Chemistry
2 answers:
Gwar [14]3 years ago
4 0

Answer:

B

Explanation:

xenn [34]3 years ago
3 0

<u>Answer: </u><em>B. Adding more protons to a positively charged body until the number of protons matches the number of electrons</em>

Option B is the appropriate response  

<u>Explanation:</u>

Utilising the equivalent number of inverse charges will kill a charged body.  

Adding more protons to a decidedly charged body until the number of protons coordinates the quantity of electrons won't kill the body since protons are emphatically charged particles. Adding more protons to an emphatically charged body would make it all the more decidedly charged.  

Enabling free electrons to escape from a contrarily charged body will kill since the more negative body leaves the negative electrons.

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The density of solid Cr is 7.15 g/cm3. How many atoms are present per cubic centimeter of Cr?
Masja [62]
To calculate the number of atoms of Cr, we first find the number of moles per unit of cubic centimeter of Cr. Then, use avogadros number for the number of atoms. Calculations are as follows:

1 cm^3 (7.15 g/cm^3) (1 mol / 51.996 g Cr) = 0.14 mol Cr

0.14 mol Cr ( 6.022 x 10^23 atoms Cr / 1 mol Cr ) = 8.28 x 10^22 atoms Cr
8 0
3 years ago
Find the volume of 56.0 grams of O2
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Answer:

39.2 L at STP

Explanation:

Convert the grams to moles first by dividing 56.0 by the molar mass of O2 (32.0) then convert to volume by multiplying by 22.4.

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3 years ago
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Yeast and other organisms can convert glucose (C6H12O6) to Ethanol (CH3CH2OH) through a process called Alcoholic Fermentation. T
Murljashka [212]

Answer:

The answer to your question is 8.28 g of glucose

Explanation:

Data

Glucose  (C₆H₁₂O₆) = ?

Ethanol (CH₃CH₂OH)

Carbon dioxide (CO₂) = 2.25 l

Pressure = 1 atm

T = 295°K

Reaction

                             C₆H₁₂O₆    ⇒    2C₂H₅OH(l) +2CO₂(g)

- Calculate the number of moles

                             PV = nRT

Solve for n

                             n = \frac{PV}{RT}

Substitution

                             n = \frac{(1)(2.25)}{(0.082)(295)}

Simplification

                            n = 0.092

- Calculate the mass of glucose

                         1 mol of glucose --------------- 2 moles of carbon dioxide

                          x                         --------------- 0.092 moles

                          x = (0.092 x 1) / 2

                          x = 0.046 moles of glucose

Molecular weight of glucose = 180 g

                       180 g of glucose ---------------  1 mol

                         x  g                    ---------------0.046 moles

                         x = (0.046 x 180) / 1

                         x = 8.28 g of glucose                                    

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3 years ago
HS0, + NaOH
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Answer: Synthesis

Explanation: I think is suynthesis

7 0
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