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3 years ago

Which quantity can be calculated using the equation E = mc2?

2 answers:

6 0

Einstein’s E= mc² equation, where E is the energy of a particle, m is the mass of the particle and c is the speed of light. This equation proves the interchangeability of energy and mass. When mass is lost it gets converted to energy that flows with the speed of light. Energy is electromagnetic radiation that flows with the speed of light.

lidiya [134]3 years ago

5 0

Energy, mass, and the speed of light squared.
(E, M, and C^2 respectively).

Hope this helped! :)

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The development of the cell theory involved ___________________________. A. different ideas from different scientists. B. the ef

pogonyaev

1. Different ideas from different scientists (such as schleiden and schwann)

2. B. Describe and examine cells

3. Sorry i don't remember this

hope this helps :)

6 0

4 years ago

Elements with great electron affinities (large negative values) often have

Svet_ta [14]

Answer:

3. small sizes and high ionization energies.

Explanation:

Hello,

Ionization energies are always related with the formation of positive ions. On the other hand, electron affinities are the negative ion equivalent, and their use is almost always confined to elements in groups 6 and 7 of the Periodic Table

Small sizes and high ionization energies turn out into great electron affinities since it is easier for an electron to be added to an atom if it is small and it has a high ionization energy to promote the aforesaid addition.

Best regards.

7 0

3 years ago

HELP!!!!! How much does a sample of Argon weigh if it occupies 25.4 L at a pressure of 2.45 atm and a temperature of 482 K?

Artist 52 [7]

Answer:

62.82 g

Explanation:

From the question,

PV = nRT.................. Equation 1

Where P = Pressure, V = Volume, n = number of moles of argon, R = molar gas constant, T = Temperature.

But,

Number of mole (n) = mass (m)/molar mass(m')

n = m/m'................... Equation 2

Substitute equation 2 into equation 1

PV = (m/m')RT.............. Equation 3

From the question, we were asked to find m.

There make m the subject of formula in equation 3

m = PVm'/RT.............. Equation 4

Given: P = 2.45 atm, V = 25.4 L, T = 482 K

Constant: R = 0.082 atm.dm³.K⁻¹.mol⁻¹, m' = 39.9 g/mol

Substitute these values into equation 4

m = (2.45×25.4×39.9)/(0.082×482)

m = 62.82 g.

5 0

3 years ago

Find the number of atoms in 237g Cu (molar mass of Cu63.55g/mol)

MakcuM [25]

In order to find the amount of atoms you have to find the moles then multiply by Avogadro's Constant (L)

mol = $\frac{MASS}{Molar Mass}$

= $\frac{237 g}{63.55 g/mol} 
$

= 3.73 mol

Number of atoms of Cu = mol × L

= 3.73 mol × (6.02 × 10²³)

= 2.245 × 10²⁴ atoms of copper

5 0

3 years ago

7. Wind, moving water, falling rocks, and roller-skating children are all examples of -

cluponka [151]

Answer:

kinetic energy

the is because all of them are moving at once

5 0

3 years ago