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Ray Of Light [21]
3 years ago
6

How many moles of carbon are in 3.7 moles of c8h11no2

Chemistry
1 answer:
sleet_krkn [62]3 years ago
8 0

Answer:- 29.6 moles of carbon.

Solution:- We have been given with 3.7 moles of C_8H_11NO_2 and asked to calculate the moles of C.

Looking at the formula of the compound, there are 8 carbons in it means 1 mol of he compound has 8 moles of C. So, if we multiply the given moles of the compound by 8 then we get the moles of C.

3.7molC_8H_11NO_2(\frac{8molC}{1molC_8H_11NO_2})

= 29.6 mol C

Hence. there are 29.6 moles of C in 3.7 moles of  C_8H_11NO_2  .

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Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

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According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

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