Answer:
- Tell us about your self
- Are your confident that you are the right candidate for this position
- why should i hire you
- Do you like working under supervision
- How do you like to work ( in a group or individually )
- What is your ultimate workplace goal
- what are your future plans
- What do you expect from the Organization when given the job
- Do you like taking on critical problems
- How long can you work in this position
Explanation:
For a job of applications engineer which require excellent technical skills, commitment to working , ability to deal well and confidently with customers a willingness to travel and very intelligent and well-balanced personality.
The ten questions you should ask Maria to determine if she is qualified for the job are :
- Tell us about your self ( functions you have )
- Are your confident that you are the right candidate for this position
- why should i hire you
- Do you like working under supervision
- How do you like to work ( in a group or individually )
- What is your ultimate workplace goal
- what are your future plans
- What do you expect from the Organization when given the job
- Do you like taking on critical problems
- How long can you work in this position
Answer:
rfvvvgfvbjjjjbvgggvvvhhjjvvvv
Explanation:
hhbbbjbnjjjjjknnnnbcfvhggcvbgffvvhbvbhbbbnbbhhhhj
Suppose a tank is made of glass and has the shape of a right-circular cylinder of radius 1 ft. Assume that h(0) = 2 ft corresponds to water filled to the top of the tank, a hole in the bottom is circular with radius in., g = 32 ft/s2, and c = 0.6. Use the differential equation in Problem 12 to find the height h(t) of the water.
Answer:
Height of the water = √(128)/147456 ft
Explanation:
Given
Radius, r = 1 ft
Height, h = 2 ft
Radius of hole = 1/32in
Acceleration of gravity, g = 32ft/s²
c = 0.6
Area of the hold = πr²
A = π(1/32)² ---- Convert to feet
A = π(1/32 * 1/12)²
A = π/147456 ft²
Area of water = πr²
A = π 1²
A = π
The differential equation is;
dh/dt = -A1/A2 √2gh where A1 = Area of the hole and A2 = Area of water
A1 = π/147456, A2 = π
dh/dt = (π/147456)/π √(2*32*2)
dh/dt = 1/147456 * √128
dh/dt = √128/147456 ft
Height of the water = √(128)/147456 ft
Answer:
Please see the attached file for complete answer.
Explanation:
Answer:
Engine not possible
Explanation:
source temperature T1 = 300 K
sink temperature T2= 283 K
therefore, carnot efficiency of the heat engine
η= 1- T_2/T_1
= 0.0566
= 5.66%
claims of work produce W = 100 kW, mass flow rate = 20 kg/s
= 1421.2 kW
now 
now 
=7%
clearly, efficiency is greater than carnot efficiency hence the engine is not possible.
