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antiseptic1488 [7]
4 years ago
6

A resistance spot welding operation is performed on two pieces of 0.040 in thick sheet steel with unit melting energy of 150 Btu

/in3. It takes 9500 A and 0.17 sec to complete a weld nugget of φ0.190 in and 0.060 in thick.
Assume the resistance of 100 micro-ohms.a) Calculate the average power density in the interface area defined by the weld nuggetb) Find the percentage of energy generated that went into formation of the weld nugget (i.e, calculate the ratio Eweld / Esource)
Engineering
1 answer:
erma4kov [3.2K]4 years ago
8 0

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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I am Lyosha [343]

Their HVACR technician advises against it because of the residential energy costs from HVAC units.

hat is the cost energy?

Energy Cost is known to be a term that connote the cost of electricity and this is one that is often related to fuel oil, gasoline, heating oil, natural gas, as well as other kinds or source of energy linked to any operation.

Hence, Since family in Florida heard about evaporative coolers as a way to cool their home without the expenses of a refrigerated air conditioning system. Their HVACR technician advises against it because of the residential energy costs from HVAC units.

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7 0
2 years ago
What dimensions are used when measuring the area of a building
scoundrel [369]

Answer:According to NEC 220.12,

“the floor area shall be calculated from outside dimensions of the buildings, dwelling unit, or other area involved.

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4 0
2 years ago
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Calculate the amount of current flowing through a 75-watt light bulb that is connected to a 120-volt circuit in your home.
vodomira [7]

Answer:

I = 0.625 A

Explanation:

Given that,

Power of the light bulb, P = 75 W

Voltage of the circuit, V = 120 V

We need to find the current flowing through it. We know that, Power is given by :

P=V\times I

I is the electric current

I=\dfrac{P}{V}\\\\I=\dfrac{75\ W}{120\ V}\\\\I=0.625\ A

So, the current is 0.625 A.

5 0
3 years ago
Pls answer and I will give a like!
lubasha [3.4K]

Answer:

a

Explanation:

6 0
3 years ago
A CL soil is being used for compacted fill on a project. A sample of the compacted soil with a total volume of 1/30 ft3 weighs 4
Genrish500 [490]

Answer:

A. 0.4

B. 1.003

C. 0.83

Explanation:

The void ratio of a mixture is defined as the ratio of the volume of voids to volume of solids.

Total volume of soil = 1/30 ft3

= 1 ft3/30 * 0.0283 m3/1 ft3

= 9.43 x 10^-4 m3

Mass of water is in the soil = 20% * 4.8

= 0.96 pounds of water

= 0.96 * 0.454

= 0.44 kg

SG = density of substance/density of water

= 2.66 * 1 kg/l

Density of the soil = 2.660 kg/l

Mass of solid = 80 %

= 80% * 4.8 * 0.454

= 1.74 kg

Volume of solids = mass/density

= 1.74/2.66

= 6.63 l

= 6.63 x 10^-4 m3.

The volume of voids is found by adding the volume of water and the volume of air.

Total volume of soil = volume of (solids + voids)

9.43 x 10^-4 = 6.63 x 10^-4 + voids

Volume of voids = 2.8 x 10^-4 m3

A.

Void ratio = volume of void : volume of solids

= 2.8 : 6.63

= 0.4

B.

Y = (1 + w) * Gs * Yw * (1 + e)

Y = moist unit weight

Yw = unit weight of water

w = moisture content of the material

Gs = pecific gravity of the solid

e = void ratio

= (1 + 0.2) * 2.66 * 0.44 * (1 + 0.4)

= 1.003.

C.

gd = Y/(1 + w)

Or

= Gs * Yw * 1/(1 + e)

= 0.83.

6 0
3 years ago
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