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3 years ago

Which factor is typically not a requisite feature of setting a career goal?

Engineering

1 answer:

Vaselesa [24]3 years ago

5 0

Answer:

Explanation: Analysing the goal of the family is not a requisite feature of setting a career goal. It is an individual person's ability and topic of interest so the family goal cannot be taken into consideration. Brainliest

Explanation:

You might be interested in

The equilibrium fraction of lattice sites that are vacant in silver (Ag) at 700°C is 2 × 10-6. Calculate the number of vacancies

True [87]

Answer:

$1.16*10^{23} vacancies/m^3$

Explanation:

Data given

temperature =700c

Density=10.35g/cm^3

but

$\frac{N_v}{N}=2*10^{-6}\\N_v=2*10^{-6}N\\$

Nv is the number of vacant site and N is the number of lattice site.

Since the number of lattice site can also b computed as

$N=\frac{p_{Ag} * N_A}{A_{AG}} \\N=\frac{6.022*10^{23} * 10.35*10^6g/m}{107.87g/mol} \\N=5.78*10^{28}atom/m^3$

if we substitute the value of the number of lattice into the first equation, we arrive at

$N_v=2*10^{-6} *5.78*10^28\\N_v=1.16*10^{23} vacancies/m^3$

4 0

4 years ago

Why does the dead man switch kill the robots manual action when pressed to hard or released

Arturiano [62]

Answer:Why does the dead man switch kill the robot's manual actions when released or pressed to hard? This is because when something goes wrong, say that the robots hits you upside the head, your reaction is either to let go or grip the switch too tight, thus the reason these actions stop all movements

Explanation:

8 0

3 years ago

Soap is a very interesting chemical. We even discussed it on the discussion board. How does it work, exactly?

soldi70 [24.7K]

Answer:

Saponification is a process in which soap is formed from mixtures of sodium or potassium salts of fatty acids. These fatty acids are reacted high temperature of At 80°C-100°C with alkali to extract salt. These alkali can be sodium hydroxide or potassium hydroxide.

Soap has both polar (ionic) and non polar molecules due to which it has characteristics of both hydrophilic substance (having tendency to mix with water) and hydrophobic substance (have tendency to mix with oils) and due to this nature it can act as an emulsifier.

An emulsifier has tendency to diffuse one liquid into another liquid which is incapable of mixing with homogeneous liquid like water.

Cleansing action takes place due to presence of ionic and non-polar properties at same time, in combination with solubility principles. The ionic end of soap molecule is the salt end. It is hydrophilic (water soluble) in nature. The non-polar end cotains long hydrocarbon chains and is hydrophobic (water repellent).

When immiscible liquids like grease or oil mixed with soap water, non polar end (hydrophobic end) absorbs the dirt which means the soap will form the micelles and trap the dirt in it. As micelles is soluble in water it will remove the dirt with it.

4 0

3 years ago

Air at 1600 K, 30 bar enters a turbine operating at steady state and expands adiabatically to the exit, where the pressure is 2.

djyliett [7]

Solution :

The isentropic efficiency of the turbine is given as :

$\eta = \frac{\text{actual work done}}{\text{isentropic work done}}$

$=\frac{m(h_1-h_2)}{m(h_1-h_{2s})}$

$=\frac{h_1-h_2}{h_1-h_{2s}}$

The entropy relation for the isentropic process is given by :

$0=s^\circ_2-s^\circ_1-R \ln \left(\frac{P_2}{P_1}\right)$

$\ln \left(\frac{P_2}{P_1}\right)=\frac{s^\circ_2-s^\circ_1}{R}$

$\frac{P_2}{P_1}=exp\left(\frac{s^\circ_2-s^\circ_1}{R}\right)$

$\left(\frac{P_2}{P_1}\right)_{s=constant}=\frac{P_{r2}}{P_{r1}}$

Now obtaining the properties from the ideal gas properties of air table :

At $T_1 = 1600 \ K,$

$P_{r1}=791.2$

$h_1=1757.57 \ kJ/kg$

Calculating the relative pressure at state 2s :

$\frac{P_{r2}}{P_{r1}}=\frac{P_2}{P_1}$

$\frac{P_{r2}}{791.2}=\frac{2.4}{30}$

$P_{r2}=63.296$

Obtaining the properties from Ideal gas properties of air table :

At $P_{r2}=63.296$ , $T_{2s}\approx 860 \ K$

Considering the isentropic relation to calculate the actual temperature at the turbine exit, we get:

$\eta=\frac{h_1-h_2}{h_1-h_{2s}}$

$\eta=\frac{c_p(T_1-T_2)}{c_p(T_1-T_{2s})}$

$\eta=\frac{T_1-T_2}{T_1-T_{2s}}$

$0.9=\frac{1600-T_2}{1600-860}$

$T_2= 938 \ K$

So, at $T_2= 938 \ K$ , $h_2=975.66 \ kJ/kg$

Now calculating the work developed per kg of air is :

$w=h_1-h_2$

= 1757.57 - 975.66

= 781 kJ/kg

Therefore, the temperature at the exit is 938 K and work developed is 781 kJ/kg.

4 0

3 years ago

Magnetic micro-generators are considered for the recovery of mechanical energy from vibrations. a)-True b)- False,

sleet_krkn [62]

Answer:

False

Explanation:

Magnetic micro generators are used to generate power making use of very small generators for generation of electricity and consists of prime movers, electric generators of quite small size or conversion devices in order to convert environmental energy like heat or vibrations into electrical energy and not mechanical energy.

Therefore, magnetic micro generators are not used for the recovery of mechanical energy from vibrations but electrical energy from them.

7 0

3 years ago