3 years ago

Can someone please help me

Chemistry

1 answer:

mrs_skeptik [129]3 years ago

8 0

The answer will be D

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How many moles are equal to 83.4 L of O2?

ladessa [460]

Answer:

$3.72mol$

Explanation:

Hello,

In this case, we consider that at STP conditions (273 K and 1 atm) we know that the volume of 1 mole of a gas is 22.4 L, thereby, for 83.4 L, the resulting moles are:

$22.4L\rightarrow 1mol\\83.4L\rightarrow X\\X=\frac{83.4L*1mol}{22.4L}=3.72mol$

This is a case in which we apply the Avogadro's law which relates the volume and the moles as a directly proportional relationship.

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CO₃²⁻ + H₂O <----------------> HCO₃⁻ + OH⁻

The chemical formula of the precipitate is Fe(OH)₃

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Ferric, Fe (III), combines with these hydroxide ions to form insoluble precipitates. Fe(OH)₃ is only partially soluble i.e., it does not completely dissociate in water. When the solutions of Fe(NO₃)₃ and K₂CO₃ are mixed, Fe(OH)₃ precipitates out due to the strong electrostatic attraction between Fe (III) and hydroxide ions.

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