If the liquid is at or above its flash point, the flame spread rate is fast, and the entire pool is engulfed within seconds. ... As the liquid temperature decreases, flame radiation must both heat the liquid to the flash point temperature and supply the heat of vaporization.
Answer:
-3.82ºC is the freezing point of solution
Explanation:
We work with the Freezing point depression to solve the problem
ΔT = m . Kf . i
ΔT = Freezing point of pure solvent - freezing point of solution
Let's find out m, molality (moles of solute in 1kg of solvent)
15 g / 58.45 g/mol = 0.257 moles of NaCl
NaCl(s) → Na⁺ (aq) + Cl⁻(aq)
i = 2 (Van't Hoff factor, numbers of ions dissolved)
m = mol /kg → 0.257 mol / 0.250kg = 1.03 m
Kf = Cryoscopic constant → 1.86 ºC/m (pure, for water)
0ºC - Tºf = 1.03m . 1.86ºC/m . 2
Tºf = -3.82ºC
Answer:
0.88mol
Explanation:
The number of moles, n, contained in a substance can be calculated using the formula;
Moles (n) = mass (m) ÷ molar mass (MM)
Molar mass of Magnesium oxide (MgO) = 24 + 16
= 40g/mol
According to the question, Mass of MgO = 35grams
Mole = 35/40
Mole = 0.875
Mole = 0.88mol
Answer: inhibitor
Explanation:
Enzymes have a shape that closely resemble that of the substrate hence they fit into the substrate by lock and key mechanism. The activity of the enzyme hinges on its similarity with the substrate in shape. Any other molecule similar to the shape of the substrate can fit into the substrate thereby preventing the enzyme from locking with the substrate. Such substances are called inhibitors. They decrease the activity of an enzyme.